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galben [10]
2 years ago
7

A mixture of three gases has a total pressure of 365 mmHg. Gas A contributes a pressure of 53 mmHg and gas B contributes a press

ure 185 mmHg. What is the partial pressure of gas C?
If you give explanation and answer, I will give you brainliest answer. :)
Chemistry
1 answer:
adoni [48]2 years ago
5 0
This one is the easiest law, but you would take 53 and 185 and add them together to get 235 and then you will minus 235 and 365 and the answer you are looking for is 130 mmHg! Hopefully this helped you!!

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Dogs use the same glycolysis and cellular processes as humans use to produce ATP. A young dog has never had much energy. He is b
scZoUnD [109]

Answer:

<h2>Dog's mitochondria lack the transport protein that transport  pyruvate ( end product of glycolysis) across the outer mitochondrial  membrane .</h2>

Explanation:

1. As given here that dog's mitochondria can use only fatty acids and also  amino acids for their respiration, and  as compared to others, Dong's cell produce more lactate then normal,  this indicate that his mitochondrial membrane is different then others.  

2. The aerobic phases of cellular respiration in eukaryotes occur within  mitochondria. These aerobic phases are the TCA Cycle and the electron transport chain. Glycolysis occurs in the cytoplasm and the products of glycolysis enter into the mitochondria to continue cellular respiration.

3. These condition shows that dog's mitochondria lack the transport protein of mitochondria that moves pyruvate across the outer mitochondrial  membrane.

3 0
3 years ago
A sample of a compound contains ​0.300 mol​ ​of carbon​ and ​1.20 mol​ ​of hydrogen​. What is the ​empirical formula of the comp
Margarita [4]

Answer:

CH4

Explanation:

The number of moles of carbon and hydrogen has been given as follows:

C = ​0.300 mol​ ​

H = ​1.20 mol

Next, we divide each mole value by the smallest (0.300)

C = 0.300 ÷ 0.300 = 1

H = 1.20 ÷ 0.300 = 4

The empirical ratio of Carbon and Hydrogen is 1:4, hence, the empirical formula is CH4

3 0
3 years ago
What is the lewis dot structure of NaBr
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3 0
3 years ago
Calculate the concentration of all species in a 0.160 m solution of h2co3.
enot [183]

             H₂CO₃ ⇔       HCO₃⁻   +     H⁺

I            0.160               0                 0

C            -x                  +x               +x

E          0.160-x          +x                +x

Ka1 = [HCO₃⁻][H⁺] / [H₂CO₃]

4.3 x 10⁻⁷ = x² / (0.160-x)   (x is neglected in 0.160-x = 0.160)

x² = 6.88 x 10⁻⁸

x = 2.62 x 10⁻⁴

             HCO₃⁻    ⇔            CO₃⁻²    +   H⁺

I          2.62 x 10⁻⁴               0                2.62 x 10⁻⁴

C          -x                            +x              +x

E       2.62 x 10⁻⁴ - x           +x              2.62 x 10⁻⁴ + x

Ka2 = [CO₃⁻²][H⁺] / [HCO₃⁻]

5.6 x 10⁻¹¹ = x(2.62 x 10⁻⁴ + x) / (2.62 x 10⁻⁴ - x)

x = 5.6 x 10⁻¹¹

Thus,

[H₂CO₃] = 0.160 - (2.62 x 10⁻⁴) = 0.16 M

[HCO₃⁻] = 2.62 x 10⁻⁴ - ( 5.6 x 10⁻¹¹) = 2.6 x 10⁻⁴ M

[CO₃⁻²] = 5.6 x 10⁻¹¹ M

[H₃O⁺] = 2.62 x 10⁻⁴ + 5.6 x 10⁻¹¹ = 2.6 x 10⁻⁴ M

[OH⁻] = 3.8 x 10⁻¹¹

8 0
2 years ago
Help!!!!!!! what is the rate of forward and reverse reactions
n200080 [17]
The rates are equal
4 0
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