A mixture of three gases has a total pressure of 365 mmHg. Gas A contributes a pressure of 53 mmHg and gas B contributes a press
1 answer:
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Answer :
(a) The number of moles of D produced can be, 6.67 moles.
(b) The volume of D prepared can be, 24.5 L
Explanation :
The given chemical reaction is:
Part (a) :
From the balanced chemical reaction, we conclude that:
As, 3 moles of A react to give 5 moles of D
So, 4 moles of A react to give moles of D
Thus, the number of moles of D produced can be, 6.67 moles.
Part (b) :
As we know that 1 moles of substance occupies 22.4 L volume of gas.
As, volume of B gives
volume of D
As, 9.8 L volume of B gives volume of D
Thus, the volume of D prepared can be, 24.5 L
Balanced chemical equation is :
It is given that the equation is in equilibrium.
We need to find what will happen if we add more is added .
By Le Chatelier's principle :
Changing the concentration of a chemical will shift the equilibrium to the side that would counter that change in concentration.
It means production of the side where content is added will decrease and concentration on other side will increase .
So , more NO would form .
Therefore, option B. is correct.
Hence, this is the required solution.