All categories

3 years ago

Draw the ketone produced from the oxidation of 2-pentanol.

1 answer:

8 0

When 2-pentanol gets oxidized you end up with 2-pentanone. In this case, since we are oxidizing a secondary alcohol you end up with a ketone. They cannot be oxidized further than that. If it was a primary alcohol you would end up with an aldehyde.

You can find the mechanism as well the molecule formula of both 2pentanol and 2pentanone attached.

You might be interested in

which organelle converts the chemical energy stored in food into compounds that are more convenient for the cell to use?

stiv31 [10]

It's the mitochondrion. It it the powerhouse of the cell and deals mainly with energy.

6 0

4 years ago

Read 2 more answers

Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of

Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}$

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles$

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

$\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles$

Finally, the mass of SiH₄ is:

$m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g$

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!

3 0

3 years ago

Can you solve the anagrams

slamgirl [31]

Compound
Property
Molecule
Magnet
????

7 0

3 years ago

What the correct answer?

alexandr402 [8]

B. Bleach and sea water should be identified as bases

Explanation:

The pH scale measures the acidic or basic nature of a substance.
Ranges from 0 to 14.
If pH is lower than 7 → the solution is an acid.
If pH is more than 7 → the solution is an basic or alkaline.
If a pH is a 7 it is neutral.

In the given question, the pH scale measures for bleach is 8 and for sea water it is 13. So, bleach is basic, not neutral and Sea water is basic too instead of acid. So, Bleach and sea water should be identified as bases.

3 0

3 years ago

Calculate the mass, in grams, of 1.2000 mol Mg₃N₂

fredd [130]

So what do you want me to do
Explanation

7 0

3 years ago