Explanation:
It is known that for first order reaction, the equation is as follows.
t = ![\frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}](https://tex.z-dn.net/?f=%5Cfrac%7B2.303%7D%7BK%7D%20log%20%5Cfrac%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bo%7D%7D%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bt%7D%7D)
t = ?, K = rate constant = 79 1/s
Initial conc. of 
= 1.68
Decompose amount of = 52% of 1.68
= 
= 0.8736
= 0.87
Now, ![[C_{4}H_{8}]_{t}](https://tex.z-dn.net/?f=%5BC_%7B4%7DH_%7B8%7D%5D_%7Bt%7D)
= (1.68 - 0.87)
= 0.81
Therefore, calculate the value of t as follows.
t =
= 
= 
= 
s
= 
Thus, we can conclude that 0.00921 s will be taken for 52% of the cyclobutane to decompose.
Answer:-
H+ + OH- --> H2O
Explanation:-
The chemical equation is NaOH + HNO3 --> NaNO3 + H2O
Now for the ionic compounds
HNO3 --> H+ + NO3 -
NaOH--> Na+ + OH-
NaNO3 --> Na+ + NO3-
Water being covalent will remain as H2O,
Hence
HNO3 + NaOH--> NaNO3 + H2O
H+ + NO3 - + Na+ + OH- --> Na+ + No3 - + H2O.
Crossing out common terms
H+ + OH- --> H2O
Answer:
Denitrogen tetraoxide
Explanation:
According to international union of pure and applied chemistry , N204
Is Denitrogen tetraoxide.
0.578 mL = 0.611 US qt = 0.509 Imp qt
Do you mean US quarts or Imperial quarts?
578 mL ×
= 0.578 L
US quarts0.578 L ×
= 0.611 qt
Imperial quarts0.578 L ×
= 0.509 qt
<span> C.The results of the Michelson-Morley experiment did not fit the theory of the luminiferous ether, so the theory had to be rejected. </span>
