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2 years ago

How many atoms are in 9.008 mol of Carbon? 0.7500 atoms 1.332 atoms 5.423 x 10^24 atoms 1.496 x 10^ -23 atoms

Chemistry

1 answer:

Zanzabum2 years ago

8 0

The number of atoms that are in 9.008 moles of carbon is

5.423 x 10^24 atoms

calculation

The number of atoms is calculated using the Avogadro's constant

That is According to Avogadro's 1 moles = 6.02 x 10^23 atoms

9.008 moles= ? atoms

by cross multiplication

= [(9.008 moles x 6.02 x 10^23 atoms) / 1 mole] = 5.423 x10^24 atoms

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1 year ago

We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to

andreyandreev [35.5K]

Answer: The correct answer is Option 5.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the NaOH.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL$

Putting all the values in above equation, we get:

$M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base.

We are given:

$n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL$

Putting values in above equation, we get:

$1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M$

Hence, the correct answer is Option 5.

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Explanation:

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Here mass of Pb(NO₃)₂ is 380 g

Molar mass of Pb(NO₃)₂ is 331.2 g/mol

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= $$ \frac{380 g }{331.2 g/mol}$

= 1.15 moles

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= 3.48 mol/L or 3.48 M

So the concentration of lead nitrate is 3.48 M.

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2 years ago

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stellarik [79]

Answer:

Explanation:

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