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Aleks [24]
3 years ago
13

What is x+2y-4-x-y+2

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:y-2

Step-by-step explanation:

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During her eight-hour shift, Sami vacuumed 104 cars. How many cars can Sami vacuum per hour?
AleksAgata [21]

Answer:

13 cars per hour

Step-by-step explanation:

She can vacuum 104 cars in 8 hours, so divide 104 by 8, 104/8, to get 13.  So she can vacuum 13 cars in 1 hour.

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Someone please help me with number 16
Zinaida [17]
This is a 45-90-45 triangle so in order to find the answer we have to multiply the hypotenuse, 6, by the square root of 2 or radical 2. Then multiply top and bottom by radical 2. Then simplify.
\frac{6}{ \sqrt{2} }  \times  \frac{ \sqrt{2} }{ \sqrt{2} }  =  \frac{6 \sqrt{2} }{2}  = 3 \sqrt{2}
3 0
3 years ago
Help me please anyone
Stels [109]

9514 1404 393

Answer:

  (2x -1) by (x +5)

Step-by-step explanation:

We presume that the dimensions of the parking lot correspond to factors of the polynomial. The factorization is ...

  2x^2 +9x -5

  = 2x^2 +10x -x -5

  = 2x(x +5) -1(x +5)

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Possible dimensions of the parking lot are (2x-1) and (x+5).

6 0
2 years ago
Lauren spent 24 hours on the computer last week. She spent 2/3 of the time doing homework. How much time did Lauren spend doing
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If Lauren spend 2/3 of her 24-hour computer time doing homework, this means she spent 16 hours doing homework. Each third of the 24 hours is 8 hours, so two thirds would be 16 hours.


6 0
3 years ago
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In ​ kite PQRS ​, TQ=3 cm and TP=4 cm. What is SP ? Enter your answer in the box.
yawa3891 [41]

Answer:

Kite is a quadrilateral in which two disjoint pairs of consecutive sides are congruent

Given: In kite PQRS

where PR and SQ are the diagonals of Kite respectively as shown in the figure given below.

Given: TQ = 3 cm and TP = 4 cm

Let PR is the main diagonal and SQ is the cross diagonal of kite PQRS as shown in figure,  also let T is the intersection point of PQRS.

By Property of Kite, diagonal SQ bisects PR at perpendicular angle i.e, 90 degree.

i,e

Then, in right angle ΔQTP

PQ = \sqrt{TQ^2+TP^2}   [Using Pythagoras theorem]

Substitute the given values of TQ and TP we have;

PQ = \sqrt{3^2+4^2} =\sqrt{9+16} =\sqrt{25} = 5 cm

Also, PQ = SP                    [by definition of kite]

therefore, the side SP = 5 cm.

4 0
2 years ago
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