suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
The answer should be 420.
~
Step-by-step explanation:
Answer:
5/6
Step-by-step explanation:
20 divide by 2 is 10
24 divide by 2 is 12
then have 10/12
10 divide by 2 is 5
12 divide by 2 is 6
answer is 5/6
Her commission would be 6% of 87,000
turn ur percent to a decimal......" of " means multiply
0.06(87,000) = $ 5220 <==
Answer:
462
Step-by-step explanation:
Using choosing, we can choose 5 pizza topping out of 11. 11!/5!/(11-5)! = 462.
Can I have Brainiest if I'm correct?