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Aleks [24]
3 years ago
13

What is x+2y-4-x-y+2

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:y-2

Step-by-step explanation:

You might be interested in
what equation is solved by the graphed systems of equations? Two linear equations that intersect at the point negative 1, negati
alexgriva [62]

Answer:

1. The equation is solved by the graphed systems of equations is:

Third option: 7x + 3 = x − 3

2. The solution to the system is:

Fourth option: (3,-1)

3. The graph of the system y = −2x + 3 and 2x + 4y = 8 is:

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

4. The solution to the system is:

Second option: Infinite solutions.

5. Bill will have read the same amount of books as Mandy in:

Fourth option: December


Step-by-step explanation:

Question 1. What equation is solved by the graphed systems of equations?

Two linear equations that intersect at the point (-1, -4)=(x,y)→x=-1, y=-4

a. 7x + 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x+3-x

6x+3=3

Subtracting 3 both sides of the equation:

6x+3-3=3-3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

b. 7x − 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x-3-x

6x-3=-3

Adding 3 both sides of the equation:

6x-3+3=-3+3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

c. 7x + 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x-3-x

6x+3=-3

Subtracting 3 both sides of the equation:

6x+3-3=-3-3

6x=-6

Dividing both sides of the equation by 6:

6x/6=-6/6

Dividing:

x=-1 equal to the intersection at x=-1, then this is the equation.

d. 7x − 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x+3-x

6x-3=3

Adding 3 both sides of the equation:

6x-3+3=3+3

6x=6

Dividing both sides of the equation by 6:

6x/6=6/6

Dividing:

x=1 different to the intersection at x=-1, then this is not the equation.


Question 2 (Multiple Choice Worth 2 points) (06.03) Solve the system 2x + 3y = 3 and 3x − 2y = 11 by using graph paper or graphing technology. What is the solution to the system?

The solution to the system is (3, -1) Fourth option

Please, see the attached graph.


Question 3 (Multiple Choice Worth 2 points) (06.03) What is the graph of the system y = −2x + 3 and 2x + 4y = 8?

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

Please, see the attached graph.


Question 4 (Multiple Choice Worth 2 points) (06.03) Solve the system y = 3x + 2 and 3y = 9x + 6 by using graph paper or graphing technology. What is the solution to the system?

Second option: Infinite solutions.

Please, see the attached graph.

Question 5 (Multiple Choice Worth 2 points) (06.03) At the end of April, Mandy told Bill that she has read 16 books this year and reads 2 books each month. Bill wants to catch up to Mandy. He tracks his book reading with a table on his door. Using his table below, what month will Bill have read the same amount of books as Mandy?

Bill

Month     Books

May             4

June            8

July             12

August        16

September 20

October      24

November  28

December  32


Books read by Mandy: y=16+2x

Numbers of months since april: x


May: x=1→y=16+2(1)=16+2→y=18 different to 4 (books read by Bill)

June: x=2→y=16+2(2)=16+4→y=20 different to 8 (books read by Bill)

July: x=3→y=16+2(3)=16+6→y=22 different to 12 (books read by Bill)

September: x=5→y=16+2(5)=16+10→y=26 different to 20 (books read by Bill)

October: x=6→y=16+2(6)=16+12→y=28 different to 24 (books read by Bill)

November: x=7→y=16+2(7)=16+14→y=30 different to 28 (books read by Bill)

December: x=8→y=16+2(8)=16+16→y=32 equal to 32 (books read by Bill)

Answer. Fourth option: December

4 0
3 years ago
A basketball player has 45 steals, 72 assists, 90 rebounds, and 432 points. What is
aalyn [17]

Answer:

5:24

Step-by-step explanation:

We're provided with the number of rebounds as 90 while the points are 432. Expressing them into ratio of rebounds to steals we have

90:432

Simplification:

Dividing both sides by 2 we obtain

45:216

Dividing both sides of the above ratio by 3 we obtain

15:72

Dividing both sides of the above ratio further by 3 we obtain

5:24

Therefore, rhe simplified ratio of rebounds ro steals is 5:24

8 0
3 years ago
Can anyone help me in Ptolemy's theorem?
GalinKa [24]

Answer:

Well, I'm not sure what you mean but Ptolemy's Theorem gives a relationship between the side lengths and the diagonals of a cyclic quadrilateral; it is the equality case of Ptolemy's Inequality. Ptolemy's Theorem frequently shows up as an intermediate step in problems involving inscribed figures.

8 0
3 years ago
Can u please help me prove those​
Alex Ar [27]

Answer:

ii

Step-by-step explanation:

A c A u B

B c A

Aç n Bc = Ac

What do you need to be explainer

6 0
3 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
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