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Komok [63]
4 years ago
14

PLEASE HELPPPP ME WITH THIS

Physics
1 answer:
lozanna [386]4 years ago
4 0
I am not so sure about this it is too difficult
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Carbon dating relies on the ratio of Carbon-12 and Carbon-14 in an organic substance
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4 years ago
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One end of a horizontal spring with force constant 76.0 N/m is attached to a vertical post. A 5.00-kg can of beans is attached t
Jobisdone [24]

Answer:

a. The speed is 2.39 m/s

b. The acceleration of the block is 10.2\frac{m}{s^{2} }

Explanation:

First, we have to do the energy balance where we consider two states, the first where the spring remains still and the second when it is stretched 0.400m:

K_{1} +U_{1}+W_{ext}=K_{2}+U_{2}\\K_{1}=0\\U_{1}=\frac{1}{2} kx^{2} _{1} =0\\W_{ext}=FΔx=(0.400m)\\

W_{ext}=20.4 Nm

U_{2} =\frac{1}{2} kx^{2} =\frac{1}{2} (76.0N/m)0.400^{2}=6.08Nm\\k_{2} =\frac{1}{2}mv^{2} _{2}  \\\frac{1}{2} mv^{2} _{2}=W_{ext}-U_{2}\\v_{2}=\sqrt{\frac{W_{ext}-U_{2}}{m} } \\v_{2}=\sqrt{\frac{20.4Nm-6.08Nm}{2.5kg} } \\v_{2}=2.39 \frac{m}{s}

To determine, the acceleration we solve the following equation for a:

F=ma\\a=\frac{F}{m} =\frac{51.0N}{5.00kg}\\a=10.2\frac{m}{s^{2} }

8 0
4 years ago
You throw a football straight up. Air resistance can be neglected. (a) When the football is 4.00 m above where it left your hand
Oksana_A [137]

Answer:

The speed of the football when it lift your hand is 8.86 m/s.

Explanation:

Given that,

Final speed of the football, v = 0.5 m/s

Height above the ground, s = 4 m

We need to find the speed of the football when it left your hand. The ball will move under the action of gravity. Using third equation of motion as:

v^2-u^2=2gs\\\\u^2=v^2-2gs\\\\u^2=(0.5)^2-2\times (-9.8)\times 4\\\\u=8.86\ m/s

So, the speed of the football when it lift your hand is 8.86 m/s. Hence, this is the required solution.

4 0
4 years ago
How is potential energy converted to thermal energy in a system?
andrezito [222]
<span> thermal energy which, by causing pressure and performing work on the pistons, is transformed into the mechanical energy that accelerates the vehicle (increasing its kinetic energy).</span>
6 0
3 years ago
A light beam in glass (n = 1.5) reaches an air-glass interface, at an angle of 60 degrees from the surface. What is the angle of
tester [92]

Answer:

θ₂ = 35.26°

Explanation:

given,

refractive index of air, n₁ = 1

refractive index of glass, n₂ = 1.5

angle of incidence, θ₁ = 60°

angle of refracted light, θ₂ = ?

using Snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1 x sin 60° = 1.5 sin θ₂

sin θ₂ = 0.577

θ₂ = sin⁻¹(0.577)

θ₂ = 35.26°

Hence, the refracted light is equal to  θ₂ = 35.26°

7 0
3 years ago
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