At angular speed of 3 rev/s, the object moves a distance equal to 3 times the circumference of the circle each second, or a distance of 3 • 2π (1.20 cm) ≈ 22.6 cm.

So, with a linear speed of 22.6 cm/s = 0.226 m/s, the object has a centripetal acceleration a of

a = (0.226 m/s)² / (0.012 m) ≈ 18.8 m/s²

directed toward the center of the circle.

7 0

3 years ago

Please help. Need help with 2d and vector problems. Please help it's urgent?

patriot [66]

Let $\theta$ denote the angle made by a given force with the positive x-axis (pointing right). So in (1), A makes an angle of 90º - 30º = 60º, and B makes an angle of -45º; and in (2), A still makes angle of 30º, B makes an angle of -15º, and C makes one of -90º.

Separate each force vector in to x- and y-components, then compute the required vector. This involves writing each given vector $\mathbf v$ as

$\mathbf v=v_x\,\mathbf i+v_y\,\mathbf j$

where

$\begin{cases}v_x=\|\mathbf v\|\cos\theta\\v_y=\|\mathbf v\|\sin\theta\end{cases}$

(1)

$\mathbf A=200\left(\cos60^\circ\,\mathbf i+\sin60^\circ\,\mathbf j\right)=100\,\mathbf i+100\sqrt3\,\mathbf j$

$\mathbf B=150\left(\cos(-45^\circ)\,\mathbf i+\sin(-45^\circ)\,\mathbf j\right)=75\sqrt2\,\mathbf i-75\sqrt2\,\mathbf j$

$\implies\mathbf A-\mathbf B\approx-6.066\,\mathbf i+67.139\,\mathbf j$

(2)

$\mathbf A=25\sqrt3\,\mathbf i+25\,\mathbf j$

$\mathbf B=25\sqrt2(1+\sqrt3)\,\mathbf i+25\sqrt2(1-\sqrt 3)\,\mathbf j$

$\mathbf C=-50\,\mathbf j$

$\implies\mathbf A+\mathbf B+\mathbf C\approx139.894\,\mathbf i-50.882\,\mathbf j$

$\implies\|\mathbf A+\mathbf B+\mathbf C\|\approx148.86$

4 0

3 years ago