Ask question

Ask question

All categories

Angelina_Jolie [31]

3 years ago

14

Electromagnetic and mechanical waves have different characteristics that make them advantageous for certain applications. Select

the reasons that mechanical waves, such as ultrasound, are used for soft tissue imaging and to identify fractures in metals

1 answer:

Minchanka [31]3 years ago

6 0

Can u give options if its not to late

You might be interested in

A grandfather clock works by swinging a pendulum back and forth with a

allochka39001 [22]

Answer:

For example, a wave with a time period of 2 seconds has a frequency of

1 ÷ 2 = 0.5 Hz.

Explanation:

8 0

2 years ago

Which of the following best describes a noncontact force

Sonja [21]

Answer:

a force that is able to act at a distance

Explanation:

:)

7 0

3 years ago

PLEASE HELP!!!! Scientists launch a rocket, and they monitor its acceleration and the force exerted by its engines. As the rocke

kobusy [5.1K]

i just took the test on edg enuity it was B.The mass of the rocket decreases as fuel is burned, so the acceleration increases.

5 0

3 years ago

Read 2 more answers

True of false metals like copper are sometimes used to fill cavities in teeth

vovikov84 [41]

Yes. Copper, mercury, and tin are all used to fill in cavities.

4 0

2 years ago

"What is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.9 m and an e

notka56 [123]

Answer:

The Magnifying power of a telescope is $M = 109.26$

Explanation:

Radius of curvature R = 5.9 m = 590 cm

focal length of objective $f_{objective}$ = $\frac{R}{2}$

⇒ $f_{objective}$ = $\frac{590}{2}$

⇒ $f_{objective}$ = 295 cm

Focal length of eyepiece $f_{eyepiece}$ = 2.7 cm

Magnifying power of a telescope is given by,

$M = \frac{f_{objective} }{f_{eyepiece} }$

$M = \frac{295}{2.7}$

$M = 109.26$

therefore the Magnifying power of a telescope is $M = 109.26$

4 0

2 years ago