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Angelina_Jolie [31]

3 years ago

14

Electromagnetic and mechanical waves have different characteristics that make them advantageous for certain applications. Select

the reasons that mechanical waves, such as ultrasound, are used for soft tissue imaging and to identify fractures in metals

1 answer:

Minchanka [31]3 years ago

6 0

Can u give options if its not to late

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The members of the track team will be able to run faster after they drink the new energy drink.” Explain why this statement is a

Mars2501 [29]

Because your taking a educated guess on what will happened if the track member drinks the energy drink

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3 years ago

Un móvil se desplaza con una rapidez inicial de 100 km/h, se le aplican los frenos con una

KIM [24]

Answer:

in English please I am quite puzzled

4 0

3 years ago

The kitchen in your house measures 10 ft by 10 ft. You need to have 50 footcandles of illumination in the room. How many 60 watt

tekilochka [14]

Answer:

<u>6 bulbs</u> are needed to illuminate the room.

Explanation:

Given:

Measurement of kitchen (A) = 10 ft by 10 ft = 100 sq. ft

Number of footcandles (n) = 50

Lumens emitted by 1 bulb = 834

Number of bulbs (N) = ?

We are also given,

1 foot candle = 1 lumen/sq. ft

So, 50 foot candles = 50 lumens/sq. ft

Now, for an area of 1 sq. ft 50 lumens are emitted.

So, for an area of 100 sq. ft, lumens emitted = 50 × 100 = 5000 lumens

Now, one bulb emits = 834 lumes

Therefore, number of bulbs required for emitting 5000 lumens is given as:

$N=\frac{Number\ of\ lumens}{Number\ of\ lumens\ by\ 1\ bulb}\\\\N=\frac{5000}{834}=5.995\approx6$

So, 6 bulbs are needed to illuminate the room.

7 0

3 years ago

During which segments are two states of matter present? the answer is D

Tomtit [17]

Answer:

2,4

Explanation:

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7 0

3 years ago

How many photons are absorbed during the dental x-ray?

MariettaO [177]

<span>E=hc/wav. len
E = (6.62 x 10^-34 x 3 x 10^8)/0.0275 x 10^-9
E = 7.22182 x 10^-15 J
To convert to eV divide by 1.6 x 10^-19
E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
Th energy, E, of a single x-ray photon in eV is = 45.36keV.

Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
n = 5.33 x 10^8 photons </span>

8 0

3 years ago