Answer:
4) three
Explanation:
Assuming you mean 1.365248×10⁷, 2% of that is:
0.02 (1.365248×10⁷) = 0.027305×10⁷
So the number is:
1.365248×10⁷ ± 0.027305×10⁷
We need to round this number so that there is uncertainty only in the last digit.
1.37×10⁷ ± 0.03×10⁷
There are three significant figures in 1.37.
Answer:A) Risk(R)= $1000
B) There is justification for spending an additional cost of $100 to prevent a corrosion whose consequence in monetary terms is $1000
Explanation:R= Risk,
P=Probability of failure
C= Consequence of failure
Mathematically, R=P ×C
10 out of 1000 carbon-steal products failed
Probability of failure= 10/1000 =0.01
The consequence of failure by corrosion given in monetary term =$100,000
Risk of failure = 0.01 × $100,000
R=$1000
Answer:
W = 30.38 N
Explanation:
Given that,
Mass of a rock, m = 3.1 kg
We need to find the weight of the rock on the surface of Earth. Weight of an object is given by :
W = mg
g is the acceleration due to gravity, g = 9.8 m/s²
W = 3.1 kg × 9.8 m/s²
= 30.38 N
So, the weight of the rock on the Earth is 30.38 N.
<span>P = energy/t = 0.0025/1E-8 = 250000 W
I(ave) = P/A = 250000/(pi*0.425E-3^2) = 4.4056732E11 W/m^2
I(peak) = 2I(ave) = 8.8113463E11 W/m^2
Electric field E = sqrt(I(peak)*Z0) = 1.8219499E7 V/m, where
free-space impedance Z0 = sqrt(µ0/e0) = 376.73031 ohms</span>
The correct answer is A. Solid Rock
