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elixir [45]
3 years ago
8

Now imagine you have several of such dipoles, and place them regularly between the plates. For this part of the pre-lab, you can

ignore any interactions between the dipoles themselves, and think of each dipole as interacting with the electric field of the plates only. What will be different now
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

Dipole is two equal but opposite charges in one. As like charges repels and unlike charges attracts each other. If dipole are in electric field region, it positive side will be attracted to the negative field and vis-versa. This will result to different movement or stationary based on the orientation of the field. If the interaction between other dipole is considered this effect may be obstructed

Explanation:

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A sample of gas in a balloon has an initial temperature of 21 ∘C and a volume of 1310 L . If the temperature changes to 70 ∘C ,
bixtya [17]

Answer:

1528.3L

Explanation:

To solve this problem we should know this formula:

V₁ / T₁ = V₂ / T₂

We must convert the values of T° to Absolute T° (T° in K)

21°C + 273 = 294K

70°C + 273 = 343K

Now we can replace the data

1310L / 294K = V₂ / 343K

V₂ = (1310L / 294K) . 343K → 1528.3L

If the pressure keeps on constant, volume is modified directly proportional to absolute temperature. As T° has increased, the volume increased too

7 0
3 years ago
A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)
elixir [45]

Answer: \Delta H^{0}=-173.72 kJ/mol

Explanation: <u>Enthalpy</u> <u>Change</u> is the amount of energy in a reaction - absorption or release - at a constant pressure. So, <u>Standard</u> <u>Enthalpy</u> <u>of</u> <u>Formation</u> is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}

Ca(OH)_{2}_{(aq)}+2HCl_{(aq)} → CaCl_{2}_{(s)}+2H_{2}O_{(l)}

Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: \Delta H^{0}= -1002.82 kJ/mol

Calcium chloride: \Delta H^{0}= -795.8 kJ/mol

Water: \Delta H^{0}= -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H]

-17.2=-1367.46+1002.82-2\Delta H

2\Delta H=17.2-364.64

\Delta H=-173.72

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

8 0
3 years ago
If you start with 89.3 g no(g) and 28.6 g h2(g), find the theoretical yield of ammonia.
Tatiana [17]
Balanced equation: 
<span>2 NO + 5 H2 ------> 2 NH3 + 2 H2O
 </span>
<span>2 moles NO react with 5 moles H2 to produce 2 moles NH3
 </span>
<span>Molar mass of NO = 30.00 g/mol </span>
<span>86.3g NO = 86.3/30.00 = 2.877 moles of NO </span>

<span>This will require: 2.877*5 / 2 = 7.192 moles of H2 </span>

<span>Molar mass of H2 = 2 g/mol </span>
<span>25.6g H2 = 25.6/2 = 12.7 mol H2. </span>
<span>You have excess H2 means the NO is limiting </span>

<span>From the balanced equation: </span>
<span>2 moles of NO will produce 2 moles of NH3 </span>
<span>2.877 moles of NO will produce 2.877 moles of NH3 </span>

<span>Molar mass NH3 = 17g/mol </span>
<span>Mass NH3 produced = 2.877 * 17 = 48.91g 

Hence the yield is = 48.91 g ~ 49 g</span>
3 0
3 years ago
Read 2 more answers
Resistance depends on which properties of a wire
Paraphin [41]
Resistance depends on there properties of a wire:
 - length (the longer the more resistance)
 - area (the less area = more resistance and vise verse more area = less resistance)
 - resistivity (the more resistivity the resistance)

Hope this helps :)
7 0
3 years ago
Read 2 more answers
We can also use the activity series to predict reactions between a metal and an acid. what are the products of the reaction fe(s
andrew11 [14]

Answer;

FeSO4 (aq) + H2 (g)

Explanation;

The reaction between iron and dilute sulfuric acid gives a salt and hydrogen gas. (iron (ii) sulfate and hydrogen gas).

The equation for the reaction is;

Fe(s) + H2SO4 (aq) = FeSO4(aq) +H2(g)

8 0
4 years ago
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