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elixir [45]
3 years ago
8

Now imagine you have several of such dipoles, and place them regularly between the plates. For this part of the pre-lab, you can

ignore any interactions between the dipoles themselves, and think of each dipole as interacting with the electric field of the plates only. What will be different now
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

Dipole is two equal but opposite charges in one. As like charges repels and unlike charges attracts each other. If dipole are in electric field region, it positive side will be attracted to the negative field and vis-versa. This will result to different movement or stationary based on the orientation of the field. If the interaction between other dipole is considered this effect may be obstructed

Explanation:

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Answer:

The answer to your question is given below

Explanation:

To convert from Particles to grams, one must have a clear understanding of Avogadro's hypothesis. From the Avogadro's hypothesis, we can easily convert from mole to particles and to grams.

Avogadro's hypothesis gives us a background understanding that 1 mole of any substance contains 6.02x10^23 particles. With this in mind we can easily convert particles to grams and grams to particles.

Now consider the following example:

1. How many particles are there in 4g of carbon?

Solution:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 particles. This implies that 1 mole of carbon contains 6.02x10^23 particles.

1 mole of carbon = 12g

Now we can say that 12g of carbon contains 6.02x10^23 particles.

If 12g of carbon contains 6.02x10^23 particles,

then 4g of carbon will contain = (4x6.02x10^23) /12 = 2.01x10^23 particles.

The next example will teach us how to convert from particles to grams..

2. What mass of helium contains 4.2x10^24 particles.

Solution:

According to Avogadro's hypothesis,

1 mole of He contains 6.02x10^23 particles.

1 mole of He = 4g

We can thus, say that 4g of He contains 6.02x10^23 particles.

1f 4g of He contains 6.02x10^23 particles,

Then Xg of He contains 4.2x10^24 Particles i.e

Xg of He = (4x4.2x10^24)/(6.02x10^23)

Xg of He = 27.91g

Therefore, 27.91g of He contains 4.2x10^24 Particles

With the above illustrations I believe you have understood how to convert from grams to particles and from particles to grams.

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3 years ago
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