What is the molality (m) of a solution that contains 76.5 g of KCl dissolved in 85.0 g of water?
1 answer:
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The standard ambient temperature and pressure are
Temperature =298 K
Pressure = 1atm
The density of gas is 1.5328 g/L
density = mass of gas per unit volume
the ideal gas equation is
PV = nRT
P = pressure = 1 atm
V = volume
n = moles
R= gas constant = 0.0821 Latm/mol K
T = 298 K
moles = mass / molar mass
so we can write
n/V = density / molar mass
Putting values
Thus molar mass of gas is 37.50g/mol
Answer: is the limiting reagent and
is the excess reagent.
Explanation:
To calculate the moles :
The balanced chemical reaction is:
According to stoichiometry :
3 moles of require = 1 mole of
Thus 0.960 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent as it is left.