What is the molality (m) of a solution that contains 76.5 g of KCl dissolved in 85.0 g of
water?
1 answer:
Answer:
76.5g KCl/74.55 grams per mole Kcl = x
molality= x/.085 kg H2O
Explanation:
well remember molality is moles of solute/kilograms of solvent. So it's the moles of KCl over 85 g of h20 converted into kg. if this makes sense.
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Answer:
NaCL + H2O
Explanation:
Your Answer Will Be Intensive Property
By being an alternative route to the reaction with a lower activation energy.
