The ligand field diagram for octahedral complex is explained here.
In a free metal ion, all the five d-orbitals are degenerate (i.e, having equal energies). But according to crystal field theory, under the influence of ligand field, degenracy of d-orbital is destroyed and they split into two or more energy levels. The difference in energy between two sets of d-orbitals is called Crystal Field Splitting Energy (CFSE). The extent of splitting depends upon the strength of ligand. A strong ligand causes greater splitting whereas weak ligand causes smaller splitting.
In octahedral complex, under the influence of ligand field, degenerate five d-orbitals split into two sets of orbitals -one is 
and another one is 
. orbital consists of 
and orbital consists of 
orbitals.
The crystal field splitting diagram for octahedral complex is attached here.
In the diagram, Δo is crystal field splitting energy (CFSE).
Answer:
d ≈ 0.098 g/mL
Explanation:
The density of a substance can be found by dividing the mass by the volume.
d=m/v
The mass of the substance is 0.221 grams and the volume is 2.25 milliliters.
m= 0.221 g
v= 2.25 mL
Substitute the values into the formula.
d= 0.221 g / 2.25 mL
Divide
d= 0.098222222 g/mL
Let’s round to the nearest thousandth. The 2 in the ten thousandths tells us to keep the 8 in the thousandth place.
d ≈ 0.098 g/mL
The density of the substance is about 0.098 grams per milliliter.
Answer:
oxidation reaction.
Explanation:
Zerovalent iron is oxidized to give
Zerovalent oxygen is reduced from
. Each year significant amounts of money are spent to prevent the corrosion of structural steel. It is inevitably a losing battle.
Answer:
C.) One mole of mercury
Explanation:
You can determine which has the greatest mass by identifying each of their atomic masses. The atomic mass represents the mass of an element per 1 mole.
Gold (Au): 196.97 g/mol
Mercury (Hg): 200.59 g/mol
Barium (Ba): 137.33 g/mol
In this case, one mole of mercury has the greatest mass.
Answer:
185.2 g/mol.
Explanation:
Solvent = Benzene
Solute = lauryl alcohol
Given:
Mass of solute = 5 g
Mass of solvent = 0.1 kg
Freezing point of solvent, Temp.f = 4.1 °C
Initial freezing point of solvent, Temp.i = 5.5 °C
Molal freezing depression constant for Benzene, kf = 5.12 °C/m
ΔTemp.f = Temp.f - Temp.i
= 5.5 - 4.1
= 1.4 °C
ΔTemp.f = kf * m
Where m = molality
m = 1.4/5.12
= 0.27 mol/kg
Molality = number of moles of solute/mass of solvent
Number of moles = 0.27/0.1
= 0.027 mol.
Molar mass = mass/number of moles
= 5/0.027
= 185.2 g/mol.
