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Black_prince [1.1K]
4 years ago
8

The electron configuration for Mo is

Chemistry
1 answer:
Vsevolod [243]4 years ago
7 0
The answer is choice A
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1) Compounds Y and Z both have the formula C9H18.
sashaice [31]

Answer:

See explanation and images attached

Explanation:

We know that the cis isomer has more heat of hydrogenation since it is less stable than the trans isomer. Since the hydrogenation of both compounds yields the same product and the hydroboration/oxidation both give a primary alcohol, they are geometric isomers and Y is the trans isomer (Image 2).

For the compound C8H12, the compound in question must be 1,5- cyclooctadiene since two moles of the same aldehyde was obtained after ozonolysis and reaction with two equivalents of hydrogen gives cyclooctane (Image 1).

5 0
3 years ago
You and your science group have been handed five mineral samples to identify. First, you sort the minerals by color. One has man
coldgirl [10]

im pretty sure it is b

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6 0
3 years ago
Why the core is metallic and the lower mantle is not.
Ugo [173]

Answer:

due to the overlaying layers of strata (layers of earth) an high pressure is created at the core. due to this it behaves like an solid rether than being a liquid... the lower mantle is not solid because in this case the overlaying strata doesn't produce that much pressure on it..

Explanation:

brainliest plz

6 0
3 years ago
What type of energy is this?
Firlakuza [10]
2 correct answers: Chemical and neither endothermic or exothermic
6 0
4 years ago
A 1.000 L vessel is filled with 1.000 mole of N2,2.000 moles of H2, and 3.000 moles of NH3. When the reaction N2(g) + 3 H2(g)⇀↽2
dlinn [17]

Answer:

The numerical value of equilibrium constant is 0.0560

Explanation:

Initial Concentration:

[NH^3]= \frac{3mol}{1l}  = 3M

[N_2] = 1M

[H_2] = 2 M

N_2 +3H_2  \rightleftarrows 2NH3

at the end, [NH_3] = 1.96 M

Thus the change is 3 - 1.96  = 1.04 M

Thus 1.04 moles of  reacted

By stoichiometry, 1.04 moles  (NH_3 \times\frac{1 mol N_2}{2 mol NH_3}) = 0.52 mol created (in addition to 1 mol already in vessel)

By similar reasoning   = 1.04 \times\frac{3}{2 } 1.56 moles  created  

Final concentrations:

[NH_3] = 1.96 M

[N_2] = 0.52 + 1 = 1.52 M

[H^2] = 1.56 + 2  = 3.56 M

K_c = \frac{[NH^3]^2}{N^2[H^2]^3}

K_c =  \frac{1.96^2}{(1.52 )\times(3.56)^3}

K_c = 0.0560

Therefore, the numerical value of equilibrium constant is 0.0560

3 0
4 years ago
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