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Svet_ta [14]
3 years ago
15

According to the theory of evolution, ______ traits will become common in a population over time.

Chemistry
1 answer:
Pavlova-9 [17]3 years ago
7 0
I believe your answer is Favorable.
Hope this helps, and happy studying~!
~{Dunsforhands}
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Using the equations 2 C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/m
Dafna11 [192]

Answer : The enthalpy for the reaction is 49.1 kJ/mol

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_6H_6 will be,

6C(s)+3H_2(g)\rightarrow C_6H_6(l)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) 2C_6H_6(g)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)    

\Delta H_1=-6271kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    

\Delta H_2=-393.5kJ/mole

(3) 2H_2(g)+O_2(g)\rightarrow 2H_2O(l)    

\Delta H_3=-483.6kJ/mole

Now we will reverse the reaction 1 and divide by 2, multiply reaction 2 by 6 and reaction 3 by 3/2 then adding all the equations, we get :

(1) 6CO_2(g)+3H_2O(l)\rightarrow C_6H_6(g)+\frac{15}{2}O_2(g)    

\Delta H_1=-\frac{-6271kJ/mole}{2}=3135.5kJ/mol

(2) 6C(s)+6O_2(g)\rightarrow 6CO_2(g)    

\Delta H_2=6\times (-393.5kJ/mole)=-2361kJ/mol

(3) 3H_2(g)+\frac{3}{2}O_2(g)\rightarrow 3H_2O(l)    

\Delta H_3=\farc{3}{2}\times (-483.6kJ/mole)=-725.4kJ/mol

The expression for enthalpy of formation of C_6H_6 will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(3135.5kJ/mole)+(-2361kJ/mole)+(-725.4kJ/mole)

\Delta H=49.1kJ/mole

Therefore, the enthalpy for the reaction is 49.1 kJ/mol

7 0
3 years ago
According to the enthalpy diagram below, which of the following statements is true?
stich3 [128]

Answer:it will be c on edg 2021

Explanation:

7 0
3 years ago
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How do rivers affect watersheds?
beks73 [17]

Answer:

Explanation:

the last one I read it

5 0
3 years ago
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Quinine is an important type of molecule that is involved in photosynthesis. The transport of electrons mediated by quinone in c
Irina18 [472]

Answer:

The heat of combustion is -25 kJ/g = -2700 kJ/mol.

Explanation:

According to the Law of conservation of energy, the sum of the heat released by the combustion reaction and the heat absorbed by the bomb calorimeter is equal to zero.

Qcomb + Qcal = 0

Qcomb = - Qcal

The heat absorbed by the calorimeter can be calculated with the following expression.

Qcal = C × ΔT

where,

C is the heat capacity of the calorimeter

ΔT is the change in temperature

Then,

Qcomb = - Qcal

Qcomb = - C × ΔT

Qcomb = - 1.56 kJ/°C × 3.2°C = -5.0 kJ

Since this is the heat released when 0.1964 g o quinone burns, the energy of combustion per gram is:

\frac{-5.0kJ}{0.1964g} =-25kJ/g

The molar mass of quinone (C₆H₄O₂) is 108 g/mol. Then, the energy of combustion per mole is:

\frac{-25kJ}{g} .\frac{108g}{1mol} =-2700kJ/mol

6 0
3 years ago
How many moles are in 17.2g k2s
Natalija [7]

Answer: 0.156 mol

Explanation:

To find the moles of 17.2 g K₂S, we need to know the molar mass to convert.

17.2g*\frac{mol}{110.256 g} =0.156 mol

3 0
3 years ago
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