Given that,
Distance in south-west direction = 250 km
Projected angle to east = 60°
East component = ?
since,
cos ∅ = base/hypotenuse
base= hyp * cos ∅
East component = 250 * cos 60°
East component = 125 km
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Answer:
The final velocity, , is gd.
Explanation:
The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;
= + 2gs
where is the final velocity of the object, is the initial velocity of the object, g is the gravitational force and s is the height.
Since the object falls from a height of d, then = 0 m/s, and s = d.
So that;
= 0 + 2gd
= 2gd
= 2gd
When the distance is , = 0 m/s.
Then;
= 2g
= g x d
When the object falls through the height , then the final velocity is gd.
Answer:
20 pound object
Explanation:
because it is closer to the ground and even though its lighter it is still that one