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aliina [53]
2 years ago
8

Two blocks, A and B, are connected by a rope. A second rope is connected to block B and a steady, horizontal tension force of T

is applied. The system moves at a constant speed across the ground. Block B experiences a friction force of f.T = 50N f = 10N
What is friction force acting on block A?
Physics
1 answer:
Oksanka [162]2 years ago
3 0

Answer:

40 N

Explanation:

We are given that

Speed of system is constant

Therefore, acceleration=a=0

Tension applied on block B=T=50 N

Friction force=f=10 N

We have to find the friction force acting on block A.

Let T' be the tension in string connecting block A and block B and friction force on block A be f'.

For Block B

T-f-T'=m_Ba

Where m_B=Mass of block B

Substitute the values

50-10-T'=m_B\times 0=0

T'==40 N

For block A

T'-f'=m_Aa

Where m_A=Mass of block A

Substitute the values

40-f'=m_A\times 0=0

f'=40 N

Hence, the friction force acting on block A=40 N

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