Answer:
19.5 m
Explanation:
Using the equation of motion,
For the first 3 seconds,
s = ut +1/2at².......................... Equation 1
Where t = time, u = initial velocity, a = acceleration, s = distance
Note: Since the car starts from rest, u = 0 m/s.
Given: a = 1.0 m/s, t = 3 s, u = 0 m/s
Substitute into equation 1
s = 0×3+1/2(3)²(1)
s = 9/2
s = 4.5
In the remaining five seconds, at a constant velocity,
s' = vt............. Equation 2
Where v = velocity, t = time.
Recall,
v = u+at
v = 0+1(3)
v = 3 m/s.
Also, t = 5 s.
Substitute into equation 2
s' = 3(5)
s' = 15 m.
Total distance = 15+4.5
Total distance = 19.5 m.
Hence the car travels 19.5 m
