True, insulators don't allow energy to pass through easily
The velocity, expressed in terms of ME, RE is given as
.
The maximum height that the rocket could reach if launched vertically is H = (¹/₂v₀²)/g.
<h3>Maximum height of the rocket</h3>
The maximum height reached by the rocket can be modeled using conservation of energy as shown below;
P.Ei + K.Ei = K.Ef + P.Ef
![M_EgR_E + \frac{1}{2} M_EV_0^2= \frac{1}{2} M_E(\frac{V_o}{10} )^2+ M_Eg(6R_E)\\\\\frac{1}{2} M_EV_0^2 - \frac{1}{2} M_E(\frac{V_o}{10} )^2 = M_Eg(6R_E) - M_EgR_E\\\\0.495M_EV_0^2= 5gM_ER_E\\\\0.495V_0^2= 5gR_E\\\\V_0 = \sqrt{\frac{5gR_E}{0.495} } \\\\V_0 = \sqrt{98.99R_E}](https://tex.z-dn.net/?f=M_EgR_E%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20M_EV_0%5E2%3D%20%5Cfrac%7B1%7D%7B2%7D%20M_E%28%5Cfrac%7BV_o%7D%7B10%7D%20%29%5E2%2B%20M_Eg%286R_E%29%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%7D%20M_EV_0%5E2%20-%20%5Cfrac%7B1%7D%7B2%7D%20M_E%28%5Cfrac%7BV_o%7D%7B10%7D%20%29%5E2%20%3D%20M_Eg%286R_E%29%20-%20M_EgR_E%5C%5C%5C%5C0.495M_EV_0%5E2%3D%205gM_ER_E%5C%5C%5C%5C0.495V_0%5E2%3D%205gR_E%5C%5C%5C%5CV_0%20%3D%20%5Csqrt%7B%5Cfrac%7B5gR_E%7D%7B0.495%7D%20%7D%20%5C%5C%5C%5CV_0%20%3D%20%5Csqrt%7B98.99R_E%7D)
<h3>Maximum height when it is launched vertically</h3>
P.E = K.E
mgH = ¹/₂mv²
H = (¹/₂v₀²)/g
Learn more about conservation of energy here: brainly.com/question/166559
"Constant change of direction" simply means on a curve.
The examples provided don't show a durn thing.
Answer: Taking into account sound is a wave, we can use the information of the displacement (generally given as a graph) to find the wavelength and frequency, then we can calculate the speed with the formula of the speed of a wave.
Explanation:
If we have the displacement graph of the sound wave, we can find its amplitude, its wavelength and period (which is the inverse of frequency).
Now, if we additionally have the frequency as data, we can use the equation of the speed of a wave:
![s=\lambda f](https://tex.z-dn.net/?f=s%3D%5Clambda%20f)
Where:
is the speed of the sound wave
is the wavelength
is the frequency