Answer: All of them are correct I think
Step-by-step explanation:
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Ratio Given
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Apple : Strawberry
4 : 5
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Find difference in parts
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5 - 4 = 1
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Find Number of strawberry cakes
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1 part = 24 cakes
5 parts = 24 x 5 = 120
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Find number of apple cakes
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1 part = 24 cakes
4 parts = 24 x 4 = 96
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Total number of cakes
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120 + 96 + 144 = 360
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Percentage of cranberry cakes
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144/360 x 100 = 40%
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Answer: 40% of the cakes are cranberry cakes
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7x + 43, that’s what I got
Answer:
therefore the solution of the system of equations is (x,y) = (4,2)
the solution is unique and therefore the the system is neither "inconsistent" nor "dependent"
Step-by-step explanation:
i) x + 2 = 6 
x = 4
ii) x - y = 2 4 - y = 2 , therefore y = 4 - 2 , therefore y = 2
iii) therefore the solution of the system of equations is (x,y) = (4,2)
iv) the solution is unique and therefore the the system is neither "inconsistent" nor "dependent"
Answer:
A) Length = 110.4 mm and width = 62.1 mm
B) A = 6855.84 mm²
C) length = 114.7 mm
width = 55.8 mm
Area = 6400.26 mm²
D) Screen with aspect ratio of 16:9 is bigger
Step-by-step explanation:
A) We are told that the aspect ratio of the phone screen = 16:9. This means that the ratio of the length to the width of the screen is 16:9.
To find the side length, we will say that;
length = 16x
width = 9x
Thus, since the edges are perpendicular, then we can use pythagoras theorem since we know that the diagonal is 127 mm
Thus;
(16x)² + (9x²)] = 127²
256x² + 81x² = 16129
337x² = 16129
x² = 16129/337
x = √(16129/337)
x = 6.9
Thus;
length = 16x = 16 × 6.9 = 110.4 mm
width = 9x = 9 × 6.9 = 62.1 mm
Length = 110.4 mm and width = 62.1 mm
B) area of screen is;
A = length × width
A = 110.4 × 62.1
A = 6855.84 mm²
C) We are told that the aspect ratio is now 18.5:9.
Thus;
length = 18.5x
width = 9x
Thus;
(18.5x)² + (9x²)] = 127²
342.25x² + 81x² = 16129
423.25x² = 16129
x² = 16129/423.25
x = √(16129/423.25)
x = 6.2
length = 18.5x = 18.5 × 6.2 = 114.7 mm
width = 9x = 9 × 6.2 = 55.8 mm
Area = 114.7 × 55.8 = 6400.26 mm²
D) Screen with aspect ratio of 16:9 is bigger
