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solong [7]
3 years ago
13

An electron moves in a straight path with a velocity of +500,000 m/s. It undergoes constant acceleration of +500,000,000,000 met

ers per second per second. How far will the electron have traveled when it reaches a velocity of +675,000 m/s? A. +0.000000175 m B. +0.00000035 m C. +0.21 m D. +0.41 m
Physics
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

Distance travelled, d = 0.21 m

Explanation:

It is given that,

Initial velocity of electron, u = 500,000 m/s

Acceleration of the electron, a = 500,000,000,000 m/s²

Final velocity of the electron, v = 675,000 m/s

We need to find the distance travelled by the electron. Let distance travelled is s. Using third equation of motion as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{(675000\ m/s)^2-(500000\ m/s^2)^2}{2\times 500000000000\ m\s^2}

s = 0.205 m

or

s = 0.21 m

So, the electron will travel a distance of 0.21 meters. Hence, this is the required solution.

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Answer:

20 hertz of frequency produced.

Explanation:

\boxed{frequency = \frac{1}{period} }

Here we will find frequency and period should be in second, here given: 0.05 seconds

using the formula:

\boxed{frequency = \frac{1}{0.05} }

\boxed{frequency =20}

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What three machines or devices depend of gravity to work?
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A<br> B <br> C <br> D<br><br> Plz help me.
Montano1993 [528]

Answer:

The correct option is;

{}               Man doing most work   {}    Box gaining the most energy

D   {}                 Y                                          Q

Explanation:

The given parameters of the question are;

The distance the box P is pushed by the Man X = 0

The force the Man X applies to the box P = x N

The distance the box Q is lifted by the Man Y = h > 0 meters

The minimum force the Man Y applies to the box Q = W, the weight of the box

Work done = Force × Distance

Energy gained = Potential energy + Kinetic Energy = (Mass × Gravity × Height = Weight × Height  = W × h) + 1/2 × Mass × Velocity²

The final velocity of either box = 0 m/s (The boxes are at rest on the ground or the shelf)

Therefore, Kinetic energy = 0 J

The work done by Man X = 0 × x = 0 J

The energy gained by the box P = W × 0 = 0 J

The work done by Man Y = W × h = W·h J

The energy gained by the box P = W × h = W·h J

We have, the work done by the man Y = W·h J is more than the work done by the man X = 0 J

The energy gained by the box P = W·h J is more than the energy gained by the box Q = 0 J

Therefore, the correct option is D, Man doing the most work is Y, box gaining the most energy is Q.

8 0
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Harrizon [31]

Answer:

Q = 2790 J

Explanation:

Mass of silver bar is 250 g

It is heated from 22.0°C to 68.5°C

The specific heat of silver is 0.240 J/g°C

It is required to find the heat absorb by the silver bar. The heat absorbed by an object when heated from one temperature to another is given by :

Q=mc\Delta T\\\\Q=250\times 0.240\times (68.5-22)\\\\Q=2790\ J

So, the heat absorbed by the silver bar is 2790 J.

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A secant and a tangent meet at a 90° angle outside the circle. What must be the difference between the measures of the interc
kozerog [31]

The difference between the measures of the intercepted arcs of the given circle is 45°.

A circle is defined as the set of points in a plane equidistant to each, such that it forms a closed two-dimensional figure, which is known as a circle.

  • A line intersecting a circle at a minimum of two distinct points is known as a secant and the line touching the circle at only one point, is known as the tangent of a circle.
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We are given that the angle subtended by secant and tangent, outside the circle is,

\theta =90^{\circ}

And angle measured inside the circle is,

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So, the difference between the measures of the intercepted arcs is,

\theta' = \theta - \phi\\\\\theta' = 90-45\\\\\theta' =45^{\circ}

Thus, we can conclude that the difference between the measures of the intercepted arcs of the given circle is 45°.

learn more about the tangent here:

brainly.com/question/14022348

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