Question

An electron moves in a straight path with a velocity of +500,000 m/s. It undergoes constant acceleration of +500,000,000,000 meters per second per second. How far will the electron have traveled when it reaches a velocity of +675,000 m/s? A. +0.000000175 m B. +0.00000035 m C. +0.21 m D. +0.41 m

Answer 1

Answer:

Distance travelled, d = 0.21 m

Explanation:

It is given that,

Initial velocity of electron, u = 500,000 m/s

Acceleration of the electron, a = 500,000,000,000 m/s²

Final velocity of the electron, v = 675,000 m/s

We need to find the distance travelled by the electron. Let distance travelled is s. Using third equation of motion as :

$v^2-u^2=2as$

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{(675000\ m/s)^2-(500000\ m/s^2)^2}{2\times 500000000000\ m\s^2}$

s = 0.205 m

or

s = 0.21 m

So, the electron will travel a distance of 0.21 meters. Hence, this is the required solution.