Answer:
The velocity of the truck after the collision is 20.93 m/s
Explanation:
It is given that,
Mass of car, m₁ = 1200 kg
Initial velocity of the car, 
Mass of truck, m₂ = 9000 kg
Initial velocity of the truck, 
After the collision, velocity of the car, 
Let 
is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.
So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.
Answer:
120 mph
Explanation:
Given:
Δx = 0.25 mi
v₀ = 0 mi/s
t = 15 s
Find: v
Δx = ½ (v + v₀) t
0.25 mi = ½ (v + 0 mi/s) (15 s)
v = 0.0333 mi/s
v = 120 mi/h
Answer:
Geographers explore both the physical properties of Earth's surface and the human societies spread across it. They also examine how human culture interacts with the natural environment, and the way that locations and places can have an impact on people.
When the cannonball is shot upwards, kinetic energy converts to gravitational potential energy (GPE).
As the ball rises, speed decreases and height increases.
So when the cannonball has reached its maximum height, all of the Kinetic energy has transferred into gravitational potential energy.
(Because at the max height, the cannonball for a brief moment has no velocity, and thus no kinetic energy)
So the GPE is 48279 Joules at it's maximum height.
