200 lb/in” = ? tons/ft?

A gas in a balloon at constant pressure has a volume of 185 mL at -125*C. What is its volume at 31.0*C? Show all work including

hichkok12 [17]

Answer:

V₂ = 379.80 mL

Explanation:

According to Charles' Law, "At constant pressure the volume of given amount of gas is directly proportional to the absolute temperature". Mathematically it is given as,

V₁ / T₁ = V₂ / T₂ ----- (1)

Data Given:

V₁ = 185 mL

T₁ = -125 °C = 148.15 K ∴ K = °C + 273.15

V₂ = ?

T₂ = 31.0 °C = 304.15 K

Solving eq. 1 for V₂,

V₂ = V₁ × T₂ / T₁

Putting values,

V₂ = 185 mL × 304.15 K / 148.15 K

V₂ = 379.80 mL

Hence, with increase in temperature the volume has also increased.

8 0

3 years ago

Calculate the amount of heat needed to melt 91.5g of solid benzene ( C6H6 ) and bring it to a temperature of 60.6°C . Round your

Inessa [10]

Answer: The amount of heat required for melting of benzene is 20.38 kJ

Explanation:

The processes involved in the given problem are:

$1.)C_6H_6(s)(5.5^oC)\rightleftharpoons C_6H_6(l)(5.5^oC)\\2.)C_6H_6(l)(5.5^oC)\rightleftharpoons C_6H_6(l)(60.6^oC)$

For process 1:

To calculate the amount of heat required to melt the benzene at its melting point, we use the equation:

$q_1=m\times \Delta H_{fusion}$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of benzene = 91.5 g

$\Delta H_{fusion}$ = enthalpy change for fusion = 127.40 J/g

Putting all the values in above equation, we get:

$q_1=91.5g\times 127.40J/g=11657.1J$

For process 2:

To calculate the amount of heat absorbed at different temperature, we use the equation:

$q_2=m\times C_{p}\times (T_{2}-T_{1})$

where,

$C_{p}$ = specific heat capacity of benzene = 1.73 J/g°C

m = mass of benzene = 91.5 g

$T_2$ = final temperature = 60.6°C

$T_1$ = initial temperature = 5.5°C

Putting values in above equation, we get:

$q_2=91.5\times 1.73J/g^oC\times (60.6-(5.5))^oC\\\\q_2=8722.05J$

Total heat absorbed = $q_1+q_2$

Total heat absorbed = $[11657.1+8722.05]J=20379.2=20.38kJ$

Hence, the amount of heat required for melting of benzene is 20.38 kJ

5 0

3 years ago

When fossil fuels are burned, they release energy stored years ago. true or false

Mariulka [41]

Answer:true

Explanation:

5 0

3 years ago

A 6.0 mol sample of C3H8(g) and a 20. mol sample of Cl2(g) are placed in a previously evacuated vessel, where they react accordi

gladu [14]

2 CH₃CH₂CH₃ + 2 Cl₂ → CH₃CH(Cl)CH₃ + CH₃CH₂CH₂Cl + 2 HCl
so according to balanced equation we notice that:
2 mole of propane reacts with 2 moles of Cl₂, so 6 moles of propane will need to react completely with 6 moles Cl₂ (This mean Cl₂ present in excess and propane is the Limiting reagent)
2 mole C₃H₈ gives 2 moles HCl
6 moles C₃H₈ gives ? moles HCl
by cross multiplication we have 6 moles of HCl formed

3 0

4 years ago

Read 2 more answers

The reaction 2KBr(s) →+ Br2(l) + 2K(s) is a Decomposition reaction

klasskru [66]

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5 0

3 years ago