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Andre45 [30]
3 years ago
5

The reaction 2KBr(s) →+ Br2(l) + 2K(s) is a Decomposition reaction

Chemistry
1 answer:
klasskru [66]3 years ago
5 0
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A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th
pogonyaev

Answer:

\boxed {\boxed {\sf 60 \%}}

Explanation:

Percent yield is a ratio of the actual yield to the theoretical yield. It is found using this formula:

\% \ yield= \frac {actual \ yield}{theoretical \  yield} *100

The actual yield is 12 liters, because that was actually produced in the lab.

The theoretical yield is 20 liters, because that was the expected yield.

\% \ yield= \frac {12 \ L}{20\ L} *100

\% \ yield= 0.6*100

\% \ yield= 60

For this reaction, the percent yield is 60%.

5 0
3 years ago
Radiation is a measure of average kinetic energy of particles in an object true or false ​
laila [671]

Answer:false

Explanation:

4 0
3 years ago
Which is more likely in a settled and sedentary community?
Andre45 [30]

Answer:

Mar 29, 2015 · Their settlements are much more permanent and include houses, storage buildings, etc. They also need preservation methods and storage techniques, unlike the nomads. Sedentary Societies were first to be seen near waterways such as rivers.

Explanation:

4 0
3 years ago
If a 185-lb patient is prescribed 145mg. What dosage is the patient receiving in mg/kg of his body weight?
Anestetic [448]

Answer:

1.728 mg/kg

Explanation:

First have to convert the patient's weight to kg

1 lb = 0.454 kg

185 lb in kg = 83.9 kg

Then we have to divide the dose per the weight of the patient

145 mg for 83.9 kg =  145/83.9

= 1.728 mg/kg

7 0
3 years ago
What is the half-life of A? What will the pressure, initially 32.1 kPa, at
kodGreya [7K]

Answer:

a) 32.09 kPa

b) 32.09 kPa

Explanation:

Given data:

rate constant = 3.56\times 10^{-7} s^{-1}

initial pressure is = 32.1 kPa

half life of A is calculated as

t_{1/2} = \frac{ln 2}{k}

t_{1/2} = \frac{ln 2}{3.56\time 10^{-7}}

t_{1/2} = = 1.956 \times 10^6 s

for calculating pressure we have follwing expression

ln p = ln P_o - kt

P =P_o e^{-kt}

a) P = 32.1 e^{-3.56\times 10^{-7} \times 10} = 32.09 kPa

b) P = 32.1 e^{-3.56\times 10^{-7} \times 10\times 60} = 32.09 kPa

5 0
3 years ago
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