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Genrish500 [490]
3 years ago
10

Ow well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure

and number of moles of gas are constant in this problem.
Using the first volume and temperature reading on the table as V1 and T1, solve for the unknown values in the table below. Remember to use the rules of significant figures when entering your numeric response.

A:
B:

C:
D:

A 2-column table with 5 rows. Column 1 is labeled Temperature (K) with entries 295, A, 250, 325, D. Column 2 is labeled Volume (L) with entries 1.0, 1.3, B, C, 0.75.
Chemistry
2 answers:
Liula [17]3 years ago
6 0

Answer:A.384 B. 0.85 c.1.1 D. 221

Explanation:

Whitepunk [10]3 years ago
3 0
I think it is A I believe
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What is the molarity of a solution that contains 14 moles of solute and 2 liters of solution?
Nata [24]

Answer:

  7 M

Explanation:

The molarity is defined as "moles per liter." Here, it is ...

  (14 moles)/(2 liters) = 7 moles/liter = 7 M

6 0
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Show your work. 37.2 moles CO2 to oxygen atoms.
Rufina [12.5K]
4 moles of oxygen (6.0zzx10

4 0
2 years ago
The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
labwork [276]

First convert grams to moles using molar mass of butane that is 58.1 g

3.50g C4H10 x (1 mol C4H10)/(58.1g C4H10) = 0.06024 mol C4H10 <span>

<span>Now convert moles to molecules by using Avogadro’s number

0.06024 mol C4H10 x (6.022x10^23 molecules C4H10)/(1 mol C4H10) = 3.627x10^22 molecules C4H10 

And there are 4 carbon atoms in 1 molecule of butane, so use the following ratio: 

3.627 x 10^22 molecules C4H10 x (4 atoms C)/(1 molecule C4H10) 
<span>= 1.45 x 10^23 atoms of carbon are present</span></span></span>

7 0
2 years ago
Read 2 more answers
Spring day characterized by day and night of equal lengths
Galina-37 [17]
<span>Day and night are not exactly of equal length at the time of the March and September equinoxes. The dates on which day and night are each 12 hours occur a few days before and after the equinoxes.</span>
3 0
3 years ago
Ancient Romans built often out of bricks and mortar. A key ingredient in their mortar was quicklime (calcium oxide), which they
velikii [3]

The question has missing information. At part 1 it is "Write a balanced chemical equation, including physical state symbols, for the decomposition of solid calcium carbonate (CaCO3) into solid calcium oxide and gaseous carbon dioxide."

Part 2. "Suppose 19.0 L of carbon dioxide gas are produced by this reaction, at a temperature of 290.0°C and pressure of exactly 1 atm. Calculate the mass of calcium carbonate that must have reacted (...)"

Answer:

41.0 g

Explanation:

1. Calcium oxide has molecular formula CaO and carbon dioxide CO₂, thus, the reaction will be:

CaCO₃(s) → CaO(s) + CO₂(g)

The equation is already balanced because there's the same number of each element on both sides.

2. First, let's calculate the number of moles of CO₂ produced by the ideal gas law:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature (290°C = 273 = 563 K).

1*19 = n*0.082*563

46.166n = 19

n = 0.4116 mol

By the stoichiometry of the reaction:

1 mol of CaCO₃ ------ 1 mol of CO₂

x ----- 0.4116 mol

By a simple direct three rule:

x = 0.4116 mol of CaCO₃.

The molar mass of the calcium carbonate is 100 g/mol, thus the mass (m) is the number of moles multiplied by it:

m = 0.4116*100

m = 41.16 g = 41.0 g

4 0
3 years ago
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