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Genrish500 [490]
3 years ago
10

Ow well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure

and number of moles of gas are constant in this problem.
Using the first volume and temperature reading on the table as V1 and T1, solve for the unknown values in the table below. Remember to use the rules of significant figures when entering your numeric response.

A:
B:

C:
D:

A 2-column table with 5 rows. Column 1 is labeled Temperature (K) with entries 295, A, 250, 325, D. Column 2 is labeled Volume (L) with entries 1.0, 1.3, B, C, 0.75.
Chemistry
2 answers:
Liula [17]3 years ago
6 0

Answer:A.384 B. 0.85 c.1.1 D. 221

Explanation:

Whitepunk [10]3 years ago
3 0
I think it is A I believe
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3 years ago
Determine the number of valence electrons for the following: [kr] 5s2 4d6
wlad13 [49]

Answer: B) 2 (as indicated by electron distribution shown), but taking into account the real properties of this element, 4,7,8 also occur (see below).

Explanation:

This is the electron complement/atomic number of ruthenium, which actually has the structure [Kr] 5s1 4d7

Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4

3 0
3 years ago
Differentiate between Acidic radical and basic radical ​
Paladinen [302]

Explanation:

<em>Acidic</em><em> </em><em>radical</em><em> </em>

<em>Acid radical is the ion formed after the removal of Hydrogen ion (H+) from an acid. Example: When H2SO4 loses H+ ion, it forms HSO4− which is an acid radical.</em><em> </em>

<em>Basic</em><em> </em><em>radical</em><em> </em>

<em> The ion formed after the removal of hydroxide ion (OH−) from a base is known as basic radical.</em>

3 0
3 years ago
The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is
WINSTONCH [101]

Each neutral carbon atom contains four valence electrons and may form up to four electron domains. Possible hybridizations include

  • sp^{3}, four electron domains, as in ethane \text{C}_2\text{H}_6
  • sp^{2}, three electron domains, as in ethene \text{C}_2\text{H}_4
  • sp, two electron domains, as in ethyne \text{C}_2\text{H}_2

Molecules of each of the three hybridization demonstrate spatial configurations that would maximizes the separation between the electron domains.

  • Carbon atoms with a sp^{3} hybridization would demonstrate a tetrahedral configuration with a bond angle of approximately 109.5\textdegree{}
  • Carbon atoms with a sp^{2} hybridization would demonstrate a triangular planar configuration with a bond angle of 120\textdegree{}
  • Carbon atoms with a sp hybridization would demonstrate a linear configuration with a bond angle of 180\textdegree{}

Bond angles are characteristic of the spatial configuration of electron domains and identifies the hybridization of the central carbon atom.

Note that each hydrogen atom contains only one valence electron and would form only single bonds. It takes two valence electrons for oxygen atoms to achieve an octet such that each oxygen form only two bonds at a single time. Therefore given the fact that the carbon is bonded to both hydrogen and oxygen, only the following hybridizations are possible

  • sp^{3} in which the oxygen atom forms a carbon-oxygen double bond with the central carbon atom;
  • sp^{2} in which the oxygen atom forms a single bond with the central carbon atom and with a second atom.
3 0
3 years ago
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