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Genrish500 [490]
4 years ago
10

Ow well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure

and number of moles of gas are constant in this problem.
Using the first volume and temperature reading on the table as V1 and T1, solve for the unknown values in the table below. Remember to use the rules of significant figures when entering your numeric response.

A:
B:

C:
D:

A 2-column table with 5 rows. Column 1 is labeled Temperature (K) with entries 295, A, 250, 325, D. Column 2 is labeled Volume (L) with entries 1.0, 1.3, B, C, 0.75.
Chemistry
2 answers:
Liula [17]4 years ago
6 0

Answer:A.384 B. 0.85 c.1.1 D. 221

Explanation:

Whitepunk [10]4 years ago
3 0
I think it is A I believe
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If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
marissa [1.9K]

The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,

Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,

Atomic mass of AL = 27 g

Molar mass of  Al₂O₃ = 101.96 g/mol

4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

read more: brainly.com/question/23982245?referrer=searchResults

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