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SVEN [57.7K]
3 years ago
8

Use the words to complete the sentences. use each word one time

Chemistry
1 answer:
svlad2 [7]3 years ago
8 0
Watershed....water....river.....streams....oceans....contaminate....nitrogen....phosphorous....subsidence...Thats the order...please give brainliest......
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When 2.5g of copper sulphate are dissolved in 500ml of water, the concentration of the solution is
GREYUIT [131]
V(H₂O)=500 mL
p(H₂O)=0.9982 g/mL

m(H₂O)=V(H₂O)p(H₂O)

mass of salt solution:
m=m(H₂O)+m(CuSO₄)=V(H₂O)p(H₂O)+m(CuSO₄)

w = m(CuSO₄)/m

w=m(CuSO₄)/{V(H₂O)p(H₂O)+m(CuSO₄)}

w=2.5/{500*0.9982+2.5}=0.004984  (0.4984%)
3 0
3 years ago
The correct IUPAC name for the following molecule is: _________
andrew-mc [135]

Answer:

A.) trans-2,3-dichloro-5-methyl-2-hexene

Explanation:

The proposed question and structure has been attached to this answer.

The<em> cis</em>- and <em>trans</em>- isomers are used to denote the alignment of the functional groups to the carbon chain side. From the diagram, we see that:

  • the two chloro groups on the main compound are in opposite directions (-<em>trans</em>), and not the same sides (-<em>cis</em>)
  • The bottom extended methyl group is on the 5th carbon as we count from left to right
  • there's a total of 6 carbon atoms with 1 double bond on the second to third carbon.

Hence the name <u>trans-2,3-dichloro-5-methyl-2-hexene</u>

8 0
3 years ago
A solution in which the [H+] is 1.0 × 10–4 mol/L is said to be
Arturiano [62]
The answer is acidic 
5 0
4 years ago
Which sequence of group 18 elements demonstrates a gradual decrease in forces of attraction
DanielleElmas [232]

Answer: Xe, Kr, Ar, Ne

Explanation:

Hope i helped please mark brainliest!

8 0
3 years ago
93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0 C.what would be the volume of this dry gas at STP
ExtremeBDS [4]
Let us assume that the oxygen behaves as an ideal gas such that we can use the ideal gas equation to solve for the number of moles of O2.
                       PV = nRT   ; n = PV/RT
Substituting the known values,
               n = (0.930 atm)(93/1000 L) / (0.0821 L.atm/mol.K)(10 + 273.15K)
                             n = 3.72 x 10^-3 mols
At STP, the volume of each mol of gas is equal to 22.4 L.
                          volume = (3.73 x 10^-3 mols) x (22.4 L/1 mol)
                           volume = 0.0833 L or 83.34 mL
5 0
4 years ago
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