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Arada [10]
3 years ago
5

The primary method in which two connected objects transfer energy by heat flow is _____.

Chemistry
2 answers:
swat323 years ago
7 0
 Conduction is heat tranfer through physical contact. Hope this helps. :)
kramer3 years ago
5 0
The primary method in which two connected objects transfer energy by heat flow is conduction.
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In a chemical equation, the symbol that takes the place of the words reacts with is an) Example HCI + KOH-KCI + H2O
rodikova [14]
An arrow means a reaction!
5 0
3 years ago
A cylinder with a movable piston contains 2.00 g of helium, He, at room temperature. More helium was added to the cylinder and t
mr Goodwill [35]

Answer : The mass of helium added to the cylinder was, 1.5 grams

Explanation :

Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

V\propto n

or,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1 = initial volume of gas = 2.00 L

V_2 = final volume of gas = 3.50 L

n_1 = initial moles of gas = \frac{\text{Mass of He}}{\text{Molar mass of He}}=\frac{2.00g}{4g/mol}=0.5mol

n_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{2.00L}{0.5mol}=\frac{3.50L}{n_2}

n_2=0.875mol

Now we have to calculate the mass of helium were added to the cylinder.

\text{Mass of He}=\text{Moles of He}\times \text{Molar mass of He}

\text{Mass of He}=0.875mol\times 4g/mol=3.5g

Mass of helium added = 3.5 - 2.00 = 1.5 g

Thus, the mass of helium added to the cylinder was, 1.5 grams

8 0
3 years ago
In Part A, you found the number of moles of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxyge
n200080 [17]

Answer:

1.40 moles.

Explanation:

The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -

4P + 5O_2 = 2P_2O_5

In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.

Since, 2 moles of P_2O_5 is formed by 4 moles of P

So, for 1.8 moles of  P_2O_5 amount of required moles of P = \frac{4}{2} \times 1.80 = 3.60

In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.

Since, 2 moles of P_2O_5 is formed by 5 moles of oxygen

So, for 1.40 moles of P_2O_5 moles of O_2 required = \frac{5}{2} \times 1.40 = 3.50

Thus as of now we have 3.60 moles of P_2O_5 and 3.50 moles of O_2.

As in the reaction of formation of P_2O_5, oxygen is the limiting reagent.

So the moles of P_2O_5 formed by the 3.50 moles of oxygen will be

P_2O_5 = \frac{2}{5} \times 3.50 = 1.40 moles.

5 0
3 years ago
7. Why is the d-block one energy level behind the s-block? Also, why would the f-block be so far behind?
Neko [114]

Answer:

7. Why is the d-block one energy level behind the s-block? Also, why would the f-block be so far behind?

me to

Explanation:

3 0
3 years ago
When an automobile engine starts, the metal parts immediately begin to absorb heat released during the combustion of gasoline. H
Eddi Din [679]

Answer:

H = 4,034,250 J

Explanation:

Mass, m = 165kg = 165,000g (Converting to grams)

Initial temperature = 15.7°C

Final temperature = 95.7°C

Temperature change, ΔT = 95.7 - 15.7 = 50°C

Specific heat capacity, c = 0.489 J/g·°C

Heat = ?

All the parameters are related with the equation below;

H = m * c * ΔT

H = 165000 * 0.489  * 50

H = 4,034,250 J

6 0
4 years ago
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