Answer: Option (a) is the correct answer.
Explanation:
A chemical formula which represents proportions between the elements present in a compound is known as empirical formula.
When chemical or molecular formula is able to be reduced to smaller whole-number ratio of the elements then both molecular and empirical formulas are considered to be the same.
Relation between molecular formula and empirical formula is as follows.
Molecular formula = n × Empirical formula
where, n is an integer.
Chemical formula of acetic acid is 
.
Chemical formula of formaldehyde is 
. It is the smaller whole-number ratio of molecular formula of acetic acid.
Chemical formula of Benzaldehyde is 
.
Chemical formula of glucose is 
.
Thus, we can conclude that formaldehyde molecules has/have the same empirical formula as acetic acid (
).
Moles (mol) = mass (g) / molar mass (g/mol)
Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol
Hence moles of NaCl in the mixture is 0.372 mol.
Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.
mole % = (moles of desired substance / Total moles of the mixture) x 100%
Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
Total moles of mixture = moles of NaCl + KCl + LiCl
Mass of KCl = 3.74 g
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g / 74.6 g/mol = 0.050 mol
Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol
Total moles = 0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
= (0.372 mol / 0.652 mol) x 100%
= 57.06%
Hence, mixture has 57.06% of NaCl as the mole percentage.
The answer to this is C. III & IV
Answer:
When silver nitrate (AgNO3) and potassium chloride (KCl) combine in their liquid state, they form two products by double displacement method.
Silver Chloride (AgCl) and Potassium Nitrate (KNO3)
The reaction is AgNO3 + KCl --- AgCl + KNO3
The precipitate formed is AgCl
Explanation:
Answer:
High conductivity
Explanation:
Metals exhibit high conductivity due to the mobility of valence electrons.
