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valentinak56 [21]
3 years ago
12

Read the chemical equation shown.

Chemistry
1 answer:
poizon [28]3 years ago
7 0
The answer is na sodium, bromine
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Wassup everyone?????
ioda

Answer:

I'm good

Explanation:

What about you?

4 0
3 years ago
What must happen before a body cell can begin mitotic cell division
Musya8 [376]

Answer: The correct answer is- Replication of DNA ( deoxyribonucleic acid) must happen before a body cell can begin mitotic cell division.

Mitotic division is a type of cell division in which a parent cell divides two identical daughter cells ( through a series of five stages that is- prophase, metaphase, anaphase, telophase, and cytokinesis) having same number of chromosomes as that of the parental cell.

It occupies the second stage of cell cycle, the first being interphase ( which has three stages that is G1, S, and G2 phase). Replication of DNA takes place in the interphase ( particulary in the S phase) so that cell is ready to divide in the mitotic phase.

Thus, replication of DNA ( deoxyribonucleic acid) must happen before a body cell can begin mitotic cell division.


3 0
3 years ago
Malonic acid, h2c3h2o4, is a diprotic acid with ka1= 1.5 x 10-3and ka2= 2.0 x 10-6. what is the concentration of the malonate an
Bess [88]

In a 0.15 m solution of malonic acid, the amount of the malonate anion, c3h2o42-, is 1.68*10^{-4} M.

Explanation:

For the first equlibria;

initial concentration of H_{2}C_{3}H_{2}OH=0.15

initial concentration of HC_{3}H_{2}O_{4}^{-} =0

initial concentration of H^{+} =0

Let concentration change of H_{2}C_{3}H_{2}OH=-x

Let concentration change of HC_{3}H_{2}O_{4}^{-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  H_{2}C_{3}H_{2}OH=0.15-x

Let concentration in equilibrium state ofHC_{3}H_{2}O_{4}^{-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{1}=\frac{x*x}{0.15-x}=\frac{1.5*10^{-3}}{1} =\frac{x^{2}}{0.15-x}

x^{2}+0.0015x-0.000225=0

Which is a quadratic equation in x, solving it gives;

x=0.01427

Therefore, HC_{3}H_{2}O_{4}^{-} =x= 0.01427M

Now for the second equlibria;

initial concentration of HC_{3}H_{2}O_{4}^{-}=0.01427

initial concentration of C_{3}H_{2}O_{4}^{2-} =0

initial concentration of H^{+} =0

Let concentration change of HC_{3}H_{2}O_{4}^{-}=-x

Let concentration change of  C_{3}H_{2}O_{4}^{2-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  HC_{3}H_{2}O_{4}^{-}=0.01427-x

Let concentration in equilibrium state ofC_{3}H_{2}O_{4}^{2-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{2}=\frac{x*x}{0.01427-x}=\frac{2.0*10^{-6}}{1} =\frac{x^{2}}{0.01427-x}

2.854*10^{-8}-(2.0*10^{-6})x=x^{2}

Therefore, C_{3}H_{2}O_{4}^{2-} =x= 1.68*10^{-4}M

<h3>What is a malonic acid?</h3>

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. For instance, the diethyl ester of malonic acid is called diethyl malonate.

Polyester and polymers both employ malonic acid as a precursor. Both the scent business and the flavoring sector utilize it. It is employed to regulate acidity. Malonic acid contributes to the production of fatty acids in people. Malonic acid has been found in a number of foods outside of the human body, including red beets, corn, scarlet beans, common beets, and cow milks, although its presence has not been defined. The group of organic substances known as dicarboxylic acids and derivatives includes malonic acid, also known as malonate or H2MALO.

To know more about malonic acid, visit:

brainly.com/question/13943912?referrer=searchResults

#SPJ4

4 0
1 year ago
Using the periodic table entry of iron below, match the numbers with what they represent.
evablogger [386]

Answer:

Answers:

1. The number 26 ↔ atomic number

2. The number 56 ↔ mass number

3. The number 4 ↔ the number of orbits

4. The number 30 ↔ number of neutrons.

5. The number 14 ↔ number of electrons in n = 3

6. The number 2 ↔ number of valence electrons.

Explanation:

The same relevant information to deal with the data reported can be found in many periodic tables.

Herewith, I copy the mentioned entry. Please see the image attached.

This is the explanation of the information shown in the entry:

1) Symbol: in the centre of the picture: Fe. It is the symbol of iron.

2) Superscript to the lef of the symbol: 26. It is the atomic number, i.e. the number of protons. Hence, this is the first match:

         1. The number 26 ↔ atomic number

3) The number 55.845 below the symbol and name of the element is the atomic mass of the element.

The atomic mass is the avereage mass of the several isotopes of the same element that exist in nature.

The particles that count for the atomic mass are the neutrons and protons, and that is reason of the called mass number, which is the sum of the neutrons and protons of a particular isotope.

An atomic mass of 55.845 means that likely there exist isotopes with mass number 56. This is, with a total number of 56 nucleons (protons and neutrons).

Since, as explained above, Fe has 26 protons, you can calcualte the number of neutrons of the 56 mass number isotope as: n = 56 - 26 = 30 neutrons.

Hence, you can match these:

        2. The number 56 ↔ mass number

        4. The number 30 ↔ number of neutrons

5. The numbers 2, 8, 14, and 2, that appear in the upper right corner of the image are the number of electrons in the different main energy levels, which is the principal quantum number (n)

They mean:

energy level (n)      number of electrons

 1                               2

2                               8

3                              14

4                             2

Hence you can match this:

5. The number 14 ↔ number of electrons in n = 3

6. The number 2 ↔ number of valence electrons

The valence electrons are the electrons in the last main energy level (here n = 4).

3. The number 4 ↔ the number of orbits

Note: orbits is not a good name for the energy levels, since orbits implies fixed paths around the nucleus and that is an overcome model.

3 0
3 years ago
Read 2 more answers
When a bond is created how many valence electrons are needed to fill an octet?
love history [14]
To fill an octet you need 8 electrons..
6 0
3 years ago
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