Answer:
H, Ca, Cl is the answer dude
Answer : Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.
Explanation :
The given molecule is
.
Three types of inter-molecular forces are present in this molecule which are Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.
- Hydrogen-bonding : when the partial positive end of hydrogen is bonded with the partial negative end of another molecule like, oxygen, nitrogen, etc.
- Dipole-dipole attraction : When the partial positively charged part of the molecule is interact with the partial negatively charged part of the molecule. For example : In case of HCl.
- London-dispersion force : This force is present in all type of molecule whether it is a polar or non-polar, ionic or covalent. For example : In case of Br-Br , F-F, etc
Hydrogen-bonding is present between the oxygen and hydrogen molecule.
Dipole-dipole forces is present between the carbon and oxygen molecule.
London-dispersion forces is present between the carbon and carbon molecule.
Answer:
0.55 g of Cu can produced by this decomposition
Explanation:
Let's think the reaction of decomposition:
2CuO → 2Cu + O₂
Ratio is 2:2. 2 moles of CuO can decompose into 2 moles of Cu and 1 mol of oxygen.
Let's convert the mass of oxyde to moles → 0.695 g. 1 mol/ 79.55 g =
8.74×10⁻³ moles
8.74×10⁻³ mol of CuO decompose to 8.74×10⁻³ moles of Cu
Let's find out the mass → 8.74×10⁻³ mol . 63.55 g/1mol = 0.55 g
Answer:
The answer to your question is below
Explanation:
Data
Aqueous acetic acid
Aqueous barium hydroxide
Formula
Acetic acid CH₃CH₂COOH
Barium hydroxide Ba(OH)₂
Neutralization reaction
CH₃CH₂COOH + Ba(OH)₂ ⇒ Ba( CH₃CH₂COO)₂ + H₂O
Barium acetate + H₂O
Barium acetate = Ba( CH₃CH₂COO)₂ = Ba(C₃H₅O₂)₂