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Temka [501]
3 years ago
9

24% of what number is 72

Mathematics
1 answer:
nignag [31]3 years ago
4 0

Answer:

300

Step-by-step explanation:

24% × x = 72

or,   24 /100

× x = 72

we have x = 72 ×  100 /24

x = 300

Hope it helps

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The length of a rectangle is 5 centimeters less than twice it’s width. The perimeter of the rectangle is 80 cm. What are the dim
algol [13]
<h3><u>The length is equal to 25.</u></h3><h3><u>The width is equal to 15.</u></h3>

l = 2w - 5

2l + 2w = 80

We have a value for l, so we can plug it into the second equation to solve for w.

2(2w - 5) + 2w = 80

Distributive property.

4w - 10 + 2w = 80

Combine like terms.

6w - 10 = 80

Add 10 to both sides.

6w = 90

Divide both sides by 6.

w = 15

Now that we have a value for w, we can plug it into the original equation to solve for l.

l = 2(15) - 5

l = 30 - 5

l = 25


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3 years ago
5x + 1 = 56<br><br> Solving 2 step equations?
frutty [35]

Answer:

the x would equal to 11 ,so x=11

4 0
3 years ago
What value of c makes the equation true? c – 23.7 = 8.5 31.2 15.2 14.2 32.2
fomenos

Answer:

32.2 is your answer for c

Step-by-step explanation:

Note the equation:

c - 23.7 = 8.5

Note the equal sign. What you do to one side, you do to the other. Isolate the c. add 23.7 to both sides

c - 23.7 (+23.7) = 8.5 (+23.7)

c = 8.5 + 23.7

Simplify.

c = 32.2

32.2 is your answer for c

~

5 0
3 years ago
What is the length of RT?
svetoff [14.1K]
10/15 x X/24 cross multiply and the answer is 16
6 0
3 years ago
Read 2 more answers
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lora16 [44]

Answer:

The proof is given below.

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC              (∵Opposite sides of parallelogram are equal)

∠DAC=∠BCE       (∵Alternate angles)

∠ADC=∠CBE        (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE


3 0
3 years ago
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