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Triss [41]
3 years ago
7

No engine is perfectly efficient because?

Engineering
2 answers:
iren2701 [21]3 years ago
8 0
B. most fuel sources create environmental change (the process of making the efficient engine will still create environmental damage)
klio [65]3 years ago
5 0

Answer:

d

Explanation:

..............................

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Three 12-V, 100-A-hr batteries are connected in series. What are the output voltage and A-hr capacity of this connection
Lera25 [3.4K]

Answer:

36V, 100A-hr

Explanation:

Since the batteries are connected in series;

i. the output voltage will be the sum of the individual voltages

ii. the current rating (A-hr) will be the same as their individual current rating (A-hr). And this is because the same current flows through the batteries.

From i,

The output voltage, V, is given by the sum of the voltages of the three batteries;

V = 12V + 12V + 12V

V = 36V

From ii,

The A-hr capacity of the connection is the same as that of the individual batteries;

100 A-hr

Therefore, the output voltage and A-hr capacity of this connection is:

36V, 100A-hr

3 0
4 years ago
Starting the vehicle's engine and listening to its operation can
miskamm [114]
I pretty sure it’s true because you can start your car and it sounds different that probably means something is wrong
3 0
3 years ago
What is meant by the dead state. Discuss its significance.
Jlenok [28]

Answer and Explanation:

Dead state can be defined as the state in which both the are ambient properties and the system properties are coincident to each other.

Since the surroundings are similar and these surroundings are fixed also, there will be no kinetic energy and also the gravitational potential energy for both the systems is also equal.

Practically, in thermodynamic studies, the Gravitational potential energy of the system is negligible. This state holds significance because it leads to the termination of all the processes that are spontaneous in nature.

4 0
4 years ago
Suggest how the following requirements might be rewritten in a
Alchen [17]

Answer:

answer letter c

Explanation:

yun anserr hhehehe

7 0
3 years ago
(a) A 10.0-mm-diameter Brinell hardness indenter produced an indentation 2.3 mm in diameter in a steel alloy when a load of 1000
vampirchik [111]

Answer:

(a)  We are asked to compute the Brinell hardness for the given indentation. for HB, where P= 1000 kg, d= 2.3 mm, and D= 10 mm.  

Thus, the Brinell hardness is computed as

HB=2P/\pi D{D-\sqrt{D^2-d^2}

=2*1000hg/\pi (10mm)[10mm-\sqrt{(1000^2-(2.3mm)^2} ]

(b)    This  part  of  the  problem  calls  for  us  to  determine  the  indentation diameter d which  will  yield  a  270  HB  when P=  500  kg.  

d=\sqrt{D^2-[D-\frac{2P}{(HB)\pi D} } ]^2\\=\sqrt{(10mm)^2-[10mm-\frac{2*500}{450( \pi10mm)} } ]^2

6 0
4 years ago
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