If you are running and you fall and everyone↓↓↓↓↓↓↓ passes you how can you still be in first place??

If E = 94.2 mJ of energy is transferred when Q = 1.66 C of charge flows through a circuit element, what is the voltage across th

Anni [7]

Answer:

V = 56.8 mV

Explanation:

When a current I flows across a circuit element, if we assume that the dimensions of the circuit are much less than the wavelength of the power source creating this current, there exists a fixed relationship between the power dissipated in the circuit element, the current I and the voltage V across it, as follows:

P = V*I

By definition, power is the rate of change of energy, and current, the rate of change of the charge Q, so we can replace P and I, as follows:

E/t = V*q/t ⇒ E = V*Q

Solving for V:

V = E/Q = 94.2 mJ /1.66 C = 56.8 mV

6 0

3 years ago

A two-phase mixture of water and steam with a quality of 0.63 and T = 300F expands isothermally until only saturated vapor rema

VMariaS [17]

Answer:

Explanation:

Hello!

To solve this problem you must follow the following steps, which are fully registered in the attached image.

1. Draw the complete outline of the problem.

2. Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)

through prior knowledge of two other properties.

3. Use temodynamic tables to find the density of water in state 1, by means of temperature and quality, with this value and volume we can find the mass.

3. Use thermodynamic tables to find the internal energy in state 1 and two using temperature and quality.

4. uses the first law of thermodynamics that states that the energy in a system is always conserved, replaces the previously found values and finds the work done.

5. draw the pV diagram using the 300F isothermal line

5 0

3 years ago

1. Which of the following is NOT an example of a lever?

Umnica [9.8K]

A staircase what makes it a lever is another objects used to displace the force better

8 0

4 years ago

An inverted tee lintel is made of two 8" x 1/2" steel plates. Calculate the maximum bending stress in tension and compression wh

Kamila [148]

Answer:

hello your question lacks some information attached is the complete question

A) (i)maximum bending stress in tension = 0.287 * 10^6 Ib-in

(ii) maximum bending stress in compression = 0.7413*10^6 Ib-in

B) (i) The average shear stress at the neutral axis = 0.7904 *10 ^5 psi

(ii) Average shear stress at the web = 18.289 * 10^5 psi

(iii) Average shear stress at the Flange = 1.143 *10^5 psi

Explanation:

First we calculate the centroid of the section,then we calculate the moment of inertia and maximum moment of the beam( find attached the calculation)

A) Calculate the maximum bending stress in tension and compression

lintel load = 10000 Ib

simple span = 6 ft

( (moment of inertia*Y)/ I ) = MAXIMUM BENDING STRESS

I = 53.54

i) The maximum bending stress (fb) in tension=

= $\frac{M_{mm}Y }{I}$ = $\frac{6.48 * 10^6 * 2.375}{53.54}$ = 0.287 * 10^6 Ib-in

ii) The maximum bending stress (fb) in compression

= $\frac{M_{mm}Y }{I}$ = $\frac{6.48 *10^6*(8.5-2.375)}{53.54}$ = 0.7413*10^6 Ib-in

B) calculate the average shear stress at the neutral axis and the average shear stresses at the web and the flange

i) The average shear stress at the neutral axis

V = $\frac{wL}{2}$ = $\frac{1000*6*12}{2}$ = 3.6*10^5 Ib

Ay = 8 * 0.5 * (2.375 - 0.5 ) + 0.5 * (2.375 - $\frac{0.5}{2}$ ) * $\frac{(2.375 - (\frac{0.5}{2} ))}{2}$

= 5.878 in^3

t = VQ / Ib = ( 3.6*10^5 * 5.878 ) / (53.54 8 0.5) = 0.7904 *10 ^5 psi

ii) Average shear stress at the web ( value gotten from the shear stress at the flange )

t = 1.143 * 10^5 * (8 / 0.5 ) psi

= 18.289 * 10^5 psi

iii) Average shear stress at the Flange

t = VQ / Ib = $\frac{3.6*10^5 * 8*0.5*(2.375*(0.5/2))}{53.54 *0.5}$

= 1.143 *10^5

4 0

4 years ago

The magic square is an arrangement of numbers in a square grid in such a way that the sum of the numbers in each row, and in eac

Yuki888 [10]

Answer:

See the explanation for the answer;

Explanation:

Matlab code is as given below

-------------------------------------------------------------------------------------Start of code

% Program to create a magic square and verify it

clc

M= magic(5)

% To find sum of elements of each row

r1= sum(M(1,:)) % Sum of row 1

r2= sum(M(2,:)) % Sum of row 2

r3= sum(M(3,:)) % Sum of row 3

r4= sum(M(4,:)) % Sum of row 4

r5= sum(M(5,:)) % Sum of row 5

% To find sum of each coloumn

c1= sum(M(:,1)) % Sum of coloumn 1

c2= sum(M(:,2)) % Sum of coloumn 2

c2= sum(M(:,3)) % Sum of coloumn 3

c2= sum(M(:,4)) % Sum of coloumn 4

c2= sum(M(:,5)) % Sum of coloumn 5

% To find sum of diagonal

d1= sum(diag(M)) % Sum of principal diagonal elements

d2= sum(diag(fliplr(M)))

-------------------------------------------------------------------------------End of code

Following results are obtained when executed.

M =

17 24 1 8 15

23 5 7 14 16

4 6 13 20 22

10 12 19 21 3

11 18 25 2 9

r1 =

65

r2 =

65

r3 =

65

r4 =

65

r5 =

65

c1 =

65

c2 =

65

c2 =

65

c2 =

65

c2 =

65

d1 =

65

d2 =

65

3 0

3 years ago