Answer:
h = 120 m
h = 60 m
when rounded to two significant digits.
Explanation:
height of the higher ball drop point
h = ½gt² = ½(9.8)5.0² = 122.5 m
lower ball drop point
h = ½(9.8)(5.0 - 1.5)² = 60.025
Answer:
It includes the preserved soft tissue of an organism
Answer:
Part a)

Part b)

Part c)
F = 2.7 N
Explanation:
Part a)
As we know that the rotational kinetic energy of the merry go round is given as


here we know that


Now we have


Part b)
Now we know that work done due to torque = change in kinetic energy




Part c)
In order to stop it in four revolutions we have



F = 2.7 N
Here, we are required to determine which combination of molecules will produce ammonia with no leftovers.
Option A: 2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.
First, it is important to know that both Nitrogen and Hydrogen used in the production of ammonia are diatomic.
Secondly, Nitrogen and Hydrogen are in the ratio 1 : 3.....
As such, the coefficient of hydrogen should be thrice that of Nitrogen to ensure that there are no leftovers.
Therefore, option A which has:
2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.
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