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dlinn [17]
3 years ago
8

When passing through a lock, which light means âapproach the lock under full control?â?

Physics
1 answer:
vekshin13 years ago
6 0
The locks referred to here are the elevators that are used to transport boats safely from one water level to another in dams. These two varying water depths allow river traffic to operate  The attached picture shows how boats enter locks in dam sites.

To regulate traffic, there are traffic lights that signal boatmen to adjust their speed when approaching the lock. The red light means to stop and to steer clear away from the lock to allows the boats inside to exit. The green light signals to enter the lock. Lastly, the amber light means approach the lock at a safe speed and under full control.

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two balls are dropped to the ground from the different heights. one is dropped 1.5s after the other, but they reach the ground a
SCORPION-xisa [38]

Answer:

h = 120 m

h = 60 m

when rounded to two significant digits.

Explanation:

height of the higher ball drop point

h = ½gt² = ½(9.8)5.0² = 122.5 m

lower ball drop point

h = ½(9.8)(5.0 - 1.5)² = 60.025

8 0
2 years ago
(b) A ray of light in glass travels towards a flat boundary with air. The angle of incidence is
aleksandr82 [10.1K]

Answer:

Total internal reflection

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2 years ago
1
lions [1.4K]

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3 years ago
Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg · m². The father
natulia [17]

Answer:

Part a)

KE = 101.4 J

Part b)

N = 0.043 revolution

Part c)

F = 2.7 N

Explanation:

Part a)

As we know that the rotational kinetic energy of the merry go round is given as

KE = \frac{1}{2}I\omega^2

KE = \frac{1}{2}84.4(\omega^2)

here we know that

\omega = 2\pi(\frac{14.8}{60})

\omega = 1.55 rad/s

Now we have

KE = \frac{1}{2}(84.4)(1.55^2)

KE = 101.4 J

Part b)

Now we know that work done due to torque = change in kinetic energy

W = KE_f - KE_i

\tau (2N\pi) = 101.4 - 0

375(2\pi N) = 101.4

N = 0.043 revolution

Part c)

In order to stop it in four revolutions we have

\tau(2\pi N) = \Delta KE

FR(2\pi N) = 101.4

F(1.5)(2\pi \times 4) = 101.4

F = 2.7 N

3 0
2 years ago
It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula:
fgiga [73]

Here, we are required to determine which combination of molecules will produce ammonia with no leftovers.

Option A: 2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.

First, it is important to know that both Nitrogen and Hydrogen used in the production of ammonia are diatomic.

Secondly, Nitrogen and Hydrogen are in the ratio 1 : 3.....

As such, the coefficient of hydrogen should be thrice that of Nitrogen to ensure that there are no leftovers.

Therefore, option A which has:

2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.

Read more:

brainly.com/question/24396848

8 0
2 years ago
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