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Varvara68 [4.7K]
3 years ago
13

Marcia pokes fun at her husband Brian because he loves to sing in the shower every morning, but

Physics
1 answer:
Masteriza [31]3 years ago
7 0

Answer:

<em>Since I can see no choices, I answered it in my own understanding.</em>

Brian - amplitude and frequency

Marcia - amplitude and longitudinal wave

Explanation:

"Sound" and "sound waves" are essential part of a person's life. They can be used for<u> communicating</u> and <u>detecting some object</u>s.

Brian loves singing in the shower which means that he is using a greater amplitude. Amplitude refers to the<em> intensity of the sound </em>or the amount of energy that a sound carries. When one sings in the shower, the sound cannot travel very far. It bounces immediately back to the person singing thus, making the sound bigger. Brian is also using a <em>different range of </em><em>frequency</em><em> compared to his normal way of talking.</em> The frequency of a normal male voice is normally 85 to 180 Hz. A person singing may have a frequency as high as 1,500 Hz.

Marcia talks loudly on the phone. This means that she is also using a greater amplitude because the intensity of her voice is big. Since she is using the telephone, this means that her voice travels in a longitudinal wave through the telephone. This allows her voice to reach to the person on the other end of the line.

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At a particular instant, an electron moves toward the east in a uniform magnetic field that is directed straight downward. the m
alexdok [17]

Answer:

towards the south

Explanation:

When the electron enters the region with magnetic field, it experiences a magnetic force perpendicular to both the directions of the electron's velocity and the magnetic field.

The direction of the force exerted on the electron can be found by using the right-hand rule:

- Index finger: direction of the velocity of the electron --> towards the east

- Middle finger: direction of the magnetic field --> downward

- Thumb: direction of the force on a positive particle --> towards the north

However, the electron is a negatively charged particle, so we must reverse the direction of the force: therefore, the force exerted on the electron is towards the south.

4 0
3 years ago
How much work w is done by the electrostatic force on the moving point charge?
V125BC [204]

As we know that electrostatic force is a conservative force

so we can say by the condition of conservative force

F_c = -\frac{dU}{dr}

here we can rearrange the above equation as

dU = - F_c.dr

now integrate both sides

\int dU = - \int F_c . dr

Now we know by the definition of work done by a force is given by

W = \int F.dr

now work done by conservative force is given as

W_c = \int F_c . dr

Now from above work done by electric field to move charge from one point to other is given as

W_{EF} = \int F_{e}.dr = - \int dU

so here work done is given as

W_{EF} = U_i - U_f

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3 0
3 years ago
A closed cylindrical tank of radius 3.5 m and height 2m is made from
Dahasolnce [82]

Explanation:

Total surface area of cylinder:

2\pi \times r(h + r) \\ 2 \times \pi \times 3.5(3.5 + 2) \\ 2\pi \times 19.25 = 120.951317 \\ 120.95  \: {cm}^{2}

sheet of metal required = 120.95 cm^2

3 0
3 years ago
Read 2 more answers
Masses m and 2m approach each other at the same speed v and collide head-on. Find the final speed of mass 2m, if mass rebounds a
antoniya [11.8K]

Answer:

<em>The rebound speed of the mass 2m is v/2</em>

Explanation:

I will designate the two masses as body A and body B.

mass of body A = m

mass of body B = 2m

velocity of body A = v

velocity of body B = -v    since they both move in opposite direction

final speed of mass A = 2v

final speed of body B = ?

The equation of conservation of momentum for this system is

mv - 2mv = -2mv + x

where x is the final momentum of the mass B

x = mv - 2mv + 2mv

x = mv

to get the speed, we divide the momentum by the mass of mass B

x/2m = v = mv/2m

speed of mass B = <em>v/2</em>

6 0
3 years ago
59. (II) The crate shown in Fig. 4-60 lies on a plane tilted at an angle A = 25.0° to the horizontal, with Mk 0.19. (a) Determin
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Explanation:

a) We need to write down first Newton's 2nd law as applied to the given system. The equations of motion for the x- and y-axes can be written as follows:

x:\;\;\;\;\;mg\sin 25° - \mu_kN = ma\;\;\;\;\;\;(1)

y:\;\;\;\;\;N - mg\cos 25° = 0\;\;\;\;\;\;\;\;\;(2)

From Eqn(2), we see that

N = mg\cos 25°\;\;\;\;\;\;\;(3)

so using Eqn(3) on Eqn(1), we get

mg\sin 25° - \mu_kmg\cos 25° = ma

Solving for the acceleration, we see that

a = g(\sin 25° - \mu_k\cos 25°)

\;\;\;\;= 2.45\:\text{m/s}^2

b) Now that we have the acceleration, we can now solve for the velocity of the crate at the bottom of the plane. Using the equation

v^2 = v_0^2 + 2ax

Since the crate started from rest, v_0 = 0. Thus our equation reduces to

v^2 = 2ax \Rightarrow v = \sqrt{2ax}

v = \sqrt{2(2.45\:\text{m/s}^2)(8.15\:\text{m})}

\;\;\;\;= 6.32\:\text{m/s}

6 0
3 years ago
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