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makvit [3.9K]
3 years ago
5

If you can’t open the lid of a jelly jar what should you do?

Physics
2 answers:
tangare [24]3 years ago
7 0

Hit in the center of the top, and it will let some air out, that will make it easier.

9966 [12]3 years ago
6 0

If I can't open the lid of a jelly jar, I'd keep trying and if I can't open the lid of a jelly jar after the MANY tries I took, I'd ask for help.

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A book starts on a shelf 1 m off of the ground. You then move the book to a higher shelf that is 3 m off of the ground. If the s
JulsSmile [24]

Answer:

Using g = 9.8: 1.02 kg, Using g = 10: 1 kg

Explanation:

E = mgh

20 = m(9.8)(3 - 1)

20 = 9.8m(2)

20 = 19.6m

m = 1.02 kg

I'm now assuming you may be using a g constant of 10, thus the close integer result, in which case the mass would be exactly 1 kilogram.

4 0
3 years ago
To make ice, a freezer that is a reverse Carnot engine extracts 37 kJ as heat at -17°C during each cycle, with coefficient of pe
Dvinal [7]

Answer:

a) 6.4 kJ

b) 43.4 kJ

Explanation:

a)

Q_{a} = Heat absorbed = 37 kJ

β  = Coefficient of performance = 5.8

W = Work done

Heat absorbed is given as

Q_{a} = β W

37 = (5.8) W

W = 6.4 kJ

b)

Q  = work per cycle required

Q  = Q_{a} + W

Q  = 37 + 6.4

Q  = 43.4 kJ

5 0
3 years ago
How do objects move under the influence of gravity?
Nady [450]

Under the influence of gravity, objects just move down to the earth.

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

4 0
3 years ago
A car with a mass of 900 kg has an initial velocity of 20 m/s. After 5 s, it has a velocity of 32 m/s.
joja [24]
See attachment file below.

Hope it helped!

3 0
3 years ago
A 23.7 kg kid slides down a
anyanavicka [17]

Answer:

\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}

Explanation:

Mass of the kid 23.7 kg.

\text { The kid is accelerating down at an angle is } 47.2^{\circ} .

^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}

We need to find the acceleration of the kid,

We know that, Parallel force acted on the kid at an angle is

F = m × g × sinθ (F = ma)

m × a = m × g × sinθ

Now, substitute the given values in the above formula to find acceleration of the kid,

23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}

23.7 × a = 232.26 × 0.733

23.7 × a = 170.24

a=\frac{170.24}{23.7}

a=7.18 \mathrm{m} / \mathrm{s}^{2}

\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}

6 0
3 years ago
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