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3 years ago

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The acceleration of a particle is given by ax(t) = -(2.00 m/s2) + (2.70 m/s3)t. (a) find the initial velocity v0x, such that the

particle will have the same x-coordinate at t = 3.80 s as it had at t = 0.

1 answer:

Alexeev081 [22]3 years ago

3 0

I’ll solve them right now just wait a few

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A tiger paces back and forth along the front of its cage, which is 8 m wide. The tiger starts from the right side of the cage, p

Black_prince [1.1K]

Answer:

The total distance is 24 m.

The tiger's resultant displacement is 8 m.

Explanation:

Given that,

Width of tiger= 8 m

Tiger starts from the right side of the cage,

Paces to the left side

$\Delta x_{1}=+8\ m$

Then, back to the right side,

$\Delta x_{2}=-8\ m$

finally, back to the left

$\Delta x_{3}=+8\ m$

We need to calculate the total distance covered

Using formula of distance

$d= x_{1}+x_{2}+x_{3}$

Put the value into the formula

$d=8+8+8$

$d=24\ m$

We need to calculate the tiger's resultant displacement

Using formula of displacement

$D=\Delta x_{1}+\Delta x_{2}+\Delta x_{3}$

Put the value into the formula

$D=8+(-8)+8$

$D=8\ m$

Hence, The total distance is 24 m.

The tiger's resultant displacement is 8 m.

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