Question

an 8 kilogram ball is fired horizontally form a 1 times 10^3 kilogram cannon initially at rest after having been fired the momentum of the ball is 2.4 time 10^3 kilogram meters per second east calculate the magnitude of the cannons velocity after the ball is fired

Answer 1

After the ball is shot, the cannon will move at a speed of 2.4 m/s.

We must learn more about the rule of conservation of linear momentum in order to locate the solution.

How can I determine the cannon's post-ball velocity magnitude?

• According to the law of conservation of linear momentum, a system's starting and ultimate velocities are equal.

• Since the cannon's initial velocity is 0 in this case, the system's initial momentum will be equal to zero as well.

• We have,

                          $m=8kg\\M=1000kg\\P_f=2.4*10^3kgm/s$

• When a cannon fires a ball, the cannon will recoil quickly and in the opposite direction of the ball's motion.

• Given that it is now moving eastward, the recoil momentum is towards the west.
• As a result, when the ball is fired, the cannon's velocity will be,

                               $P_f=MV\\V=\frac{P_f}{M} =2.4m/s$

Thus, we can infer that the cannon's maximum speed once the ball is fired is 2.4 m/s.

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Answer 2

The magnitude of the cannons velocity after the ball is fired will be 2.4m/s.

To find the answer, we have to know more about the law of conservation of linear momentum.

How to find the magnitude of the cannons velocity after the ball is fired?

• The law of conservation of linear momentum states that, the initial momentum of a system will be equal to the final momentum.
• Here, then initial momentum of the system will be equal to zero, since the initial velocity of the cannon is equal to zero.
• Given that,

                      $M_B=8kg\\M_C=1*10^3 kg\\P_f=2.4*10^3 kgm/s.$

• When the ball is fired from the canon, then the cannon will have a recoil velocity in the opposite direction of motion of the ball.
• Since it has a final momentum towards east, the recoil momentum will be in the west.
• Thus, the velocity of the cannon after when the ball is fired will be,

                   $P_f=M_CV_C\\V_C=\frac{P_f}{M_C}=\frac{2.4*10^3}{1*10^3} =2.4m/s \\west$

Thus, we can conclude that, the magnitude of the cannons velocity after the ball is fired is 2.4m/s.

Learn more about the law of conservation of linear momentum here:

brainly.com/question/28106285

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