% error = 3.4 %
Percent error = |accepted value - experimental value|/accepted value × 100%
∴ % error = |355 mL – 343 mL|/355 mL × 100 % = |12|/355 × 100 % = 3.4 %
Answer:
— The molality of chloride ions in 300g of water is. A) 1.00 molal. B) 0.500 molal. C) 0.0553 molal. D) 0.111 molal.
Answer:
0.03682 mL of mercury
Explanation:
We know the density of the mercury which is 13.58 g/mL
density = mass / volume
volume = mass / density
Now we can calculate the volume of 0.5 g of mercury:
volume = 0.5 / 13.58 = 0.03682 mL of mercury
