<span>(a) The balanced equation shows that 2 moles of water result from 5 moles of
oxygen that reacts, so that is 0.4 times as many moles of water as O2. So if we
have 2.50 moles of oxygen reacting, we produce 0.4 times that amount, or
1.0 mole of water.
(b) The molecular weight of acetylene is 26 and that of O2 is 32, so we can set
up the proportion: 2.25 gm. / 52 = x gm. / 160
Then x grams = (2.25)(160) / 52 = 6.923 grams of O2 are required.
(c) The balanced equation shows that twice as many moles of CO2 are produced
as we have acetylene reacting. If 78.0 grams of acetylene react, that is 3 moles
so we produce twice that, or 6 moles of CO2. The molecular weight of CO2 is 44,
so we have 44 times 6, or 264 grams of carbon dioxide produced.
(d) If we collect 186 grams of CO2, the percentage yield is:
186/264 = 0.7045, or 70.45 percent yield.
Whew! Hope this answers all parts of your question!</span><span>
</span>
C6H12O6 (s) + 6O2 (g) + 6CO2 (g) + 6H2O(l)
I would say #3 I’m sorry if it’s wrong tho
This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.
- The alkanes are non- polar solvents.
- The alkanes are immiscible in water but freely miscible in other non-polar solvent .
- The alkanes are consisting of weak dipole dipole bonds can not breaks the strong hydrogen bond.
- The alkanes having only carbon (C) and hydrogen (H) atom which is bonded by a single bonds only.
- The alkanes posses weak force of attraction that is weak van der waals force of attraction.
The ethane, propane, butane, belong to alkanes family.The alkanes are also considers as saturated hudrocarbons. Ethane is found in gaseous stae Ethane is the second alkane followed by propane followed by butane.
learn about butane
brainly.com/question/14818671
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