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Jet001 [13]
2 years ago
10

if a steel spoon were to be plated with silver, state what would be suitable as the anode, cathode, electrolyte​

Chemistry
2 answers:
Tresset [83]2 years ago
7 0

Answer:

The anode will be silver

The cathode will be the steel spoon

The electrolyte will be silver nitrate

Explanation:

Pls mark BRAINLIEST

e-lub [12.9K]2 years ago
4 0

Answer:

tae hahahah joke lang hindi ko alam ehh

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The diagram shows a simple model of an event that is part of the rock cycle. image Which type of event is most likely occurring
Bezzdna [24]

Answer: D. the hardening of liquid magma that leads to igneous rock

Explanation:

5 0
2 years ago
How do I do number 64?
shutvik [7]
They are isotopes because isotopes have the same number of protons (atomic number) but can have different numbers of neutrons + protons (atomic mass).
5 0
3 years ago
Pis
loris [4]

Answer:

5.00×10-19 J

Explanation:

E = hv

but v = c ÷ wavelength

E = (6.626×10-34) × ((3×10^8)÷(398×10-9))

= 4.9945×10-19

≈5.00×10-19

Hope this helps

8 0
2 years ago
A piece of antimony with a mass of 17.41 g is submerged in 46.3 cm3 of water in a graduated cylinder. The water level increases
kobusy [5.1K]

Answer:

6.696 g/cm3

Explanation:

From the question;

Mass = 17.41g

Volume of water before = 46.3 cm3

Volume of water after = 48.9 cm3

Volume of antimony = Volume after - Volume before = 48.9 - 46.3 = 2.6 cm3

Density = Mass / Volume

Density = 17.41 / 2.6 = 6.696 g/cm3

8 0
3 years ago
In the reaction: C6H6 + O2 = CO2 + H2O If 26.2 grams of C6H6 is reacted in a 0.250-liter container and this reaction is carried
Lelechka [254]
<h3>Answer:</h3>

43.33 atm

<h3>Explanation:</h3>

We are given;

Mass of C₆H₆ = 26.2 g

Volume of the container = 0.25 L

Temperature = 395 K

We are required to calculate the pressure inside the container;

First, we calculate the number of moles of C₆H₆

Molar mass of C₆H₆ =  78.1118 g/mol.

But; Moles = mass ÷ Molar mass

Moles of  C₆H₆ = 26.2 g ÷  78.1118 g/mol.

                         = 0.335 moles C₆H₆

Second, we calculate the pressure, using the ideal gas equation;

Using the ideal gas equation, PV = nRT , Where R is the ideal gas constant, 0.082057 L.atm/mol.K

Therefore;

P = nRT ÷ V

  = (0.335 mol × 0.082057 × 395 K) ÷ 0.25 L

 = 43.433 atm

Therefore, the pressure inside the container is 43.33 atm

6 0
3 years ago
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