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Roman55 [17]
3 years ago
15

All question are compulsory​

Chemistry
2 answers:
Vikki [24]3 years ago
8 0
The Answer to your question is no
lys-0071 [83]3 years ago
7 0

Answer:

is this question or you just asking I can't understand.

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Check my answer plz!! 100 points. Tell me if they are wrong! 1. You have three elements, A, B, and C, with the following electro
Artyom0805 [142]

look good w small changes below:

Answer:  


AB is an ionic compound. The electronegativity difference between A and B is greater.  


AC is an ionic compound. The electronegativity difference between A and C is greater.  


BC is a covalent compound because the electronegativity difference between C and B is small.


everything else look good!

6 0
3 years ago
Read 2 more answers
2.50 g of Zn is added to 5.00 g of HCl
Debora [2.8K]
Zn+2HCl ----> 2ZnCl2 + H2

For 2.50 g of Zn

Mass per mol = 2.50/molar mass of Zn = 2.50/65.38 = 0.0382 g/mol
There are two moles of ZnCl2 and total mass = 2*0.0382*molar mass of ZnCl2 = 2*0.0382*136.286 = 10.42 g

For 2 g of HCl

Mass per mol = 2/2*molar mass of HCl = 2/ (2*36.46) = 0.0274 g/mol
For the two moles of ZnCl2, mass produced = 2*0.0274*136.286 = 7.48 g

It can be noted that 2 g of HCl produced less amount of ZnCl and thus it is the limiting reagent.
5 0
3 years ago
A gas at a pressure of 360 torrs and a volume of 750 ml. If the pressure becomes 1.5 atm what is the new volume?
r-ruslan [8.4K]

Answer:

V₂ = 236.84 mL

Explanation:

The relation between pressure and volume is inverse.

We can write it as follows :

P_1V_1=P_2V_2

We have,

P₁ = 360 torrs, V₁ = 750 mL, P₂ = 1.5 atm = 1140 torr.

So,

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{360\times 750}{1140}\\\\V_2=236.84\ mL

So, the new volume of the gas is 236.84 mL.

4 0
3 years ago
In order to reduce dependence on imported oil, the government of Jalica has imposed minimum fuel-efficiency requirements on all
liubo4ka [24]

Answer:

(B) The Jalican government did not intend the new fuel-efiiciency requirement to be a pollution-reduction measure.

Explanation:

What it was expressed is about to reduce dependence on imported oil.

6 0
3 years ago
A 5.00 mL sample of hydrochloric acid is titrated with 0.1293 M ammonia (a base). If the titration required 28.15 mL of ammonia,
Sladkaya [172]

Answer:

1. C = 0.73 M.

2. pH = 0.14

       

Explanation:

The reaction is the following:

HCl + NH₃ ⇄ NH₄⁺Cl⁻

From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

n_{a} = n_{b}

Where "a" is for acid and "b" is for base.

The number of moles is:

n = C*V  

Where "C" is for concentration and "V" for volume.

C_{a}V_{a} = C_{b}V_{b}

C_{a} = \frac{0.1293 M*28.15 mL}{5.00 mL} = 0.73 M

Hence the initial concentration of the acid is 0.73 M.

The original pH of the acid is given by:

pH = -log([H^{+}])

pH = -log(0.73) = 0.14          

Therefore, the original pH of the acid is 0.14.

I hope it helps you!                  

4 0
3 years ago
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