Answer:
The O is being oxidized, but at the same time, is being reducted.
Explanation:
H₂O₂(l) + ClO₂(aq) → ClO₂(aq) + O₂(g)
In this reaction, we have 4 compounds:
Hydrogen peroxide
Chlorine dioxide (twice)
Oxygen
In both dioxide, the Cl acts with +4 in oxidation state; the oxygen acts with -2.
Oxgen in ground state has 0, as oxidation number.
In peroxide, the H acts with +1 but the oxygen acts with -1.
Peroxide is making the oxidation number from the O in the ClO₂, to decrease (reduction) and to increase in the O, at the ground state.
Hydrogen peroxide is a good reducing and oxidizing agent at the same time.
Formula unit mass is defined as the sum of the mass of all the atoms each multiplied its atomic masses that are present in the empirical formula of a compound. It is expressed in amu.
Atomic mass of calcium = 40 amu
Atomic mass of chlorine = 35.5 amu
Formula mass of CaCl2 = (1 x 40) + (2 x 35.5) = 111amu.
Answer:
- Aldehydes
- A hydrogen atom
- Oxygen
Explanation:
Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only <u>aldehydes</u> can be easily oxidized because there is<u> a hydrogen atom</u> next to the carbonyl and oxidation does not require<u> oxygen </u>
Answer:
Na2CO3 is the formula for sodium carbornate
250 kJ/87.9 KJ per mole Cl2 * 71g/mole= 202 g It is D for plato users
