Answer:
1. D
2. B
3. A
4. C
Step-by-step explanation:
1. Vertical angles are a pair of opposite angles formed by the intersection of lines. Choice D has two lines intersecting, and two opposite angles formed by it.
2. Adjacent angles are two angles that have a common vertex and common side but do not overlap. Choice B is two angles with a common vertex and common side, and they don't overlap.
3. Supplementary angles are angles that add up to 180 degrees/make a straight angle. Choice A has two angles that add up to 180 degrees, and the two angles combined make a straight angle/line.
4. Two angles are called complementary angles if they add up to 90 degrees and form a right angle. Choice C has two angles that form a right triangle, meaning it adds up to 90 degrees.
Hi there!

We can begin by multiplying by its conjugate:

Simplify using the identity:


Take the square root of the expression:

Multiply again by the conjugate to get a SINGLE term in the denominator:

Simplify:

Use the above trig identity one more:

Cancel out sinA:

Split the fraction into two:

Recall:

Simplify:

Domain: is x is equal to or more than-3, it is also equal to and less than 1.
Range: Y is equal to or greater than 2, it is also equal to and less than 5.
The first option is greater.