Answer:
C=y=sin1/2x
Step-by-step explanation:
As given in the graph:
Amplitude= 1
period=2π
Finding function of sin that have period of 4π and amplitude 1
A: y=1/2sinx
Using the formula asin(bx-c)+d to find the amplitude and period
a=1/2
b=1
c=0
d=0
Amplitude=|a|
=1/2
Period= 2π/b
=2π
B: y=sin2x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=2
c=0
d=0
Amplitude=|a|
=1
Period= 2π/2
=π
C: y=sin1/2x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=1/2
c=0
d=0
Amplitude=|a|
=1
Period= 2π/1/2
=4π
D: y=sin1/4x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=1/4
c=0
d=0
Amplitude=|a|
=1
Period= 2π/1/4
=8π
Hence only c: y=sin1/2x has period of 2π and amplitude 1
The magnitude of the resulting vector, u - v, is approximately 5.83
and its angle of direction is approximately 59.04°.
<h3>How to find the magnitude of the resulting vector?</h3>
We want to subtract vector v from vector u.
We are given;
v = <2, -3> = 2i - 3j
u = <5, 2> = 5i + 2j
u - v = 5i + 2j - (2i - 3j)
= 5i + 2j - 2i + 3j
= 3i + 5j
Resultant vector = √(3² + 5²)
Resultant vector = √34 ≈ 5.83
Angle of direction of resultant vector is;
tan θ = (5/3)
θ = tan⁻¹(5/3)
θ = 59.04°
Read more about Magnitude of Vector at; brainly.com/question/3184914
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Answer:
1^2 is one squared which means
1x1
1^3 is
1x1x1
2^4 is
2x2x2x2 which equals 16
Step-by-step explanation:
Answer:
Step-by-step explanation:
6/x^2 + 2 x = 7
2 x^3 - 7 x^2 = -6 (for x!=0)
(2 (x^3 - 3 x^2 + 3))/x^2 = 1
<span>The fittable function seems to be 2 x^2+4 x+7.
So C (167)</span>
