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3 years ago

10

I need help with this question please, if anyone would be kind enough to give me the correct answer, in return I would gladly r

ate a 5 star and give brainliest (:

1 answer:

belka [17]3 years ago

5 0

-4(3n + 5) is the answer

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Find the value of <br> (16/81)^3/4

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Step-by-step explanation:

This question looks quite awful coz it might be (16+81)^3/4 rather than being (16/81)^3/4....But, if it is (16/81)^3/4 the answer is 1.92636657×10^-3

hope you find it helpful....Thanks very much...

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Step-by-step explanation:

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Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

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$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

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