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OverLord2011 [107]
3 years ago
8

A marching band is practicing. The band director sees the drum major hit a drum. How far away is the director if he hears the dr

umbeat in 0.40 seconds? The speed of sound is 300 m/s
Physics
2 answers:
Elan Coil [88]3 years ago
7 0
V = S/t
-> 300 = S/0.4
-> 300 x 0.4 = S
-> S = 120m
castortr0y [4]3 years ago
5 0
Distance = (speed) x (time)

Distance = (300 m/s) x (0.4 sec) = 120 meters
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madreJ [45]
<span>Mass of the electron = 9.1 x 10 ^ -28g = 9.1 x 10 ^ -31kg Velocity of the electron = 1.7 x 10 ^ 4 We have Planck Constant h = 6.626 x 10 ^ -34 Wavelength of the electron w = h/mv w = 6.626 x 10 ^ -34 / ((9.1 x 10 ^ -31)(1.7 x 10 ^ 4)) = 6.626 x 10 ^ -34 / 15.47 x 10 ^ -27 = 0.428312 x 10 ^ -7 = 4.28 x 10 ^ -8 m</span>
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3 years ago
An electron and a proton, starting from rest, are accelerated through an electric potential difference of the same magnitude. in
Yakvenalex [24]
The charges are the same in absolute value, so the change of potential energy is the same. That means that the change in kinetic energy is also the same. Then:

1 = Ke/Kp = m_e *v_e^2 / m_p * v_p^2, or

v_e/v_p = sqrt( m_p/m_e),

So the speed of the electron will be sqrt( m_p/m_e) times greater than the speed of the proton
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3 years ago
A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work
yawa3891 [41]

The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

  • Mass of car; m = 200kg
  • Acceleration of the car; a = 0.5m/s^2
  • Distance covered by the car; d = 10m

Work done; W = \ ?

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

Work\ done = f * d

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; Force \ F = m * a

We substitute our given values into the expression

F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2

Next we substitute our values into the expression of work done above.

Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J

Therefore, the work done by the man pushing the car over the given distance is 1000J.

Learn more about work done: brainly.com/question/26115962

7 0
2 years ago
The percentage of water vapor in the air compared to the maximum amount of water vapor that air can contain at a particular temp
natali 33 [55]

Answer:

Relative humidity %

Explanation:

  • The relative humidity is the percentage of the water vapor content at a particular temperature and pressure to the maximum amount of water vapor content the air can hold at those conditions.
  • When the relative humidity of the air becomes 100% then there occurs precipitation on the earth from the atmosphere (specifically troposphere, which accounts for the weather changes).
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5 0
4 years ago
A 0.30 kg softball has a velocity of 15 m/s at an angle of 35 degrees below the horizontal just before making contact with the b
jarptica [38.1K]

Answer:

a) 5.03 kg m/s

b) 10.03 kg m/s

Explanation:

Hi!

Let us consider the origin of coordinates at the pitcher, and pointing directly towards the initial direction of the ball. Therefore, the angle of the velocity with respect to the x axis is -35° (below the horizontal).

The components of the initial momentum are:

px = (0.3 kg)(15 m/s) cos(-35° ) = 4.5 cos(-35° ) kg m/s = 3.69 kg m/s

py = 4.5 sin(-35° ) kg m/s = -2.581 kg m/s

The final momentum will be:

a)

pfx = 0

pfy = - (20 m/s) (0.3 kg) = -6 m/s

And the difference in momentum is:

dpy = pfy - py = -3.419 kg m/s

dpx = pfx - px = -3.69 kg m/s

And its magnitude:

dp = √(dpy^2 + dpx^2) = 5.03 kg m/s

b)

pfx = -6 kg m/s

pfy = 0

And the difference in momentum is:

dpx = pfx - px = -9.69 kg m/s

dpy = pfy - py = 2.581 kg m/s

And its magnitude:

dp = √(dpy^2 + dpx^2) = 10.03 kg m/s

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