The work done by the man pushing the car over the given distance is 1000J.
Given the data in the question;
Work done;
Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;
Where f is force applied and d is distance travelled.
To determine the work done by the man, we first solve for the force applied F.
From Newton's Second Law;
We substitute our given values into the expression
Next we substitute our values into the expression of work done above.
Therefore, the work done by the man pushing the car over the given distance is 1000J.
Learn more about work done: brainly.com/question/26115962
Answer:
The wavelength of the interfering waves is 3.14 meters.
Explanation:
Given that,
The equation of standing wave that is formed by interfering two harmonic waves (travelling opposite direction) is given by :
........(1)
The general equation of standing wave is given by :
..............(2)
On comparing equation (1) and (2), we get :
k = 2
We know that,
So, the wavelength of the interfering wave is 3.14 meters. Hence, this is the required solution.
<u>Answer :</u>
(a) The Initial temperature of the steam is 247.557°C
(b) The enthalpy change per unit mass of the steam is -1771 kJ/kg
(c) The final pressure is 1555 kPa, and the liquid vapor mixture contains small mass of vapor.
<u>Explanation :</u>
From the given statements, we know
Initial steam pressure () = 3.5 MPa
Degree of Super heat = 5°C
Saturation Temperature () = 242.557°C [From Steam Table]
Now, the Initial temperature () of steam is given by-
=
+ Degree of Superheat
= 242.557 + 5 = 247.557°C
(b)To find: The enthalpy change per unit mass of the steam is
We know enthalpy (h) change is given by
Δh = –
From steam Table, properties of the gas at state 1 and state 2
= 2821.1 kJ/kg
= 1049.7 kJ/kg
On substituting the values, we get
or, Δh = 1049.7 - 2821.1 = -1771 kJ/kg
(c) To Find: The final pressure of the liquid vapor mixture contains small mass of vapor.
We find that the gas at the final position, i.e., at position 3
Final Temperature () = 200°C [Given] ……………………………..(1)
Specific Volume () = Specific Volume (
) = 0.00123
/kg ….....(2)
Using steam table for corresponding values of (1) and (2), we get
Final Pressure = 1555 kPa
Dryness fraction () = 0.0006.