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GenaCL600 [577]
3 years ago
6

Why is it illegal to manufacture fireworks without a license

Chemistry
1 answer:
victus00 [196]3 years ago
3 0

Illegal Explosives. Illegal explosives associated with the fireworks season are inherently dangerous because of their composition and unpredictability. Homemade explosives can pose a particular risk for injury because the people making them often lack knowledge and experience in manufacturing fireworks.

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True. Our earth Is getting hotter due to global warming.
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How many grams of magnesium would contain the same number of atoms as 26.982 grams of aluminum?
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Three elements that are likely to have similar chemical and physical properties are
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Which of the following is not a result when a change to an equilibrium system is applied? (2 points)
Ray Of Light [21]
It should be increasing the rate of the forward reaction will cause a shift to the left because the external stress, which is the increase in rate, will cause the reaction to be unbalanced, and to reach equilibrium it needs to shift to the right.
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4 years ago
Read 2 more answers
A sample of an ideal gas in a cylinder of volume 2.67 L at 298 K and 2.81 atm expands to 8.34 L by two different pathways. Path
Igoryamba

Explanation:

  • For path A, the calculation will be as follows.

As, for reversible isothermal expansion the formula is as follows.

            W = -2.303 nRT log(\frac{V_2}{V_1})

Since, we are not given the number of moles here. Therefore, we assume the number of moles, n = 1 mol.

As the given data is as follows.

              R = 8.314 J/(K mol),          T = 298 K ,

          V_{2} = 8.34 L,    V_{1} = 2.67 L

Now, putting the given values into the above formula as follows.

            W = -2.303 nRT log(\frac{V_2}{V_1})

   = -2.303 \times 1 \times 8.314 J/K mol \times 298 log(\frac{8.34}{2.67})

     = -2.303 \times 1 \times 8.314 J/K mol \times 298 \times 0.494

    = -2818.68 J

Hence, work for path A is -2818.68 J.

  • For path B, the calculation will be as follows.

Step 1: When there is no change in volume then W = 0

Hence, for step 1, W = 0

Step 2: As, the gas is allowed to expand against constant external pressure P_{external} = 1.00 atm.

So,              W = -P_{external} \times \Delta V

Now, putting the given values into the above formula as follows.

               W = -P_{external} \times \Delta V

                   = -1 atm \times (8.34 L - 2.67 L)  

                    = -5.67 atm L

As we known that, 1 atm L = 101.33 J

Hence, work will be calculated as follows.

       W = -\frac{101.33 J}{1 atm L} \times 5.67 atm L

            = -574.54 J

Therefore, total work done by path B = 0 + (-574.54 J)

                        W = -574.54 J

Hence, work for path B is -574.54 J.

3 0
4 years ago
8.) If 396 g of Carbon Dioxide (CO2) are produced, what mass of Oxygen
KengaRu [80]

Answer:

480 g of oxygen.

Explanation:

C3H8 + 5O2 --->  3CO2 + 4H2O

Using the molar masses:

3*12 + 6*16 g of CO2 were formed from 10*16 g O2

132g  g CO2 from 160 g O2

1g CO2 from (160/132) g O2

396 g from (160/132) * 396

= 480 g of oxygen.

3 0
3 years ago
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