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natka813 [3]
2 years ago
13

Annie has a soccer ball and a kickball she kicks each ball with the same force the soccer ball accelerates at 3 m/s to the secon

d power and the kickball accelerates at 5 m/s to the second power Use Newtons laws to describe why the kickball has a greater acceleration
Chemistry
1 answer:
Alexxandr [17]2 years ago
8 0

Answer:

Because of less weight kick ball has more acceleration.

Explanation:

Acceleration of kick ball:

5 m/s

Acceleration of soccer ball:

3 m/s

Newton's second law:

According to newton's second law the acceleration of object depends upon two variables.

1) Mass of object

2) Force acting on it

Mathematical expression:

a = f/m

a = acceleration

f = force

m = mass

The force on balls are same thus the acceleration is depend upon the masses of balls.

The soccer ball has more weight that's why its acceleration is less while kick ball is lighter and thus its acceleration will more.

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A solution is prepared by dissolving 27.0 g of urea [(NH2)2CO], in 150.0 g of water. Calculate the boiling point of the solution
andrew11 [14]

<u>Answer:</u> The boiling point of solution is 101.56°C

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure water = 100°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point elevation constant = 0.52°C/m.g

m_{solute} = Given mass of solute (urea) = 27.0 g

M_{solute} = Molar mass of solute (urea) = 60 g/mol

W_{solvent} = Mass of solvent (water) = 150.0 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=1\times 0.52^oC/m\times \frac{27\times 1000}{60\times 150}\\\\\text{Boiling point of solution}=101.56^oC

Hence, the boiling point of solution is 101.56°C

5 0
3 years ago
when you receive fluid in the hospital, it is often 0.9% saline solution. what would happen if the nurse used distilled water in
jasenka [17]

Answer:

The distilled water solution would be hypotonic to your blood cells, so they would gain water, swell, and possibly burst.

8 0
3 years ago
Which is a combination of pollutants that mix with water vapor in a city or near large highways and factories?
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8 0
3 years ago
A student conducts an experiment by placing a wooden stick in a cup of sugar solution. Over the next few weeks, sugar crystals f
Ipatiy [6.2K]

Answer: In order to be alive there must be cells present and since sugar does not contain cells it is not alive.

Explanation:

8 0
2 years ago
A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh
Vaselesa [24]

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

3 0
3 years ago
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