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vlada-n [284]
3 years ago
10

Carbon forms two oxides in which the weight of oxygen combines with 1 g of carbon

Chemistry
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

This is based on the masses of one element, that will be combined with a fixed mass of the other element.

Explanation:

This is based on the masses of one element, that will be combined with a fixed mass of the other element. Thoses masses are in a ratio.

This state we can find in 'The Law of Multiple Proportions, which is part of Dalton's atomic theory

We see that in the 2 compounds, the masses of oxygen, that combine with a fixed mass of carbon , will be in proportion.

For the first oxide we have 1g carbon per 1.33 g Carbon

1g /1.33g  = 0.752

For the second oxide we have 1g carbon per 2.66g Carbon

1g/2.66g = 0.376

Dividing the mass O per g C of the second (larger value) compound:

2.66 / 1.33 = 2   which is the same as 0.752 / 0.376

thus, it means that the masses of oxygen that combine with carbon are in a 2:1 ratio.

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2) Z = 3: Cu(NO3)2*3H2O

Explanation:

<u>Step 1: </u>Data given

Mass of copper (II) nitrate hydrate, Cu(NO3)2•zH2O = 34.8243 grams

Mass of substance after heating = 27.0351 grams

Molar mass of Cu(NO3)2 = 187.56 g/mol

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<u>Step 2:</u> Calculate mass of water

The mass of water is the mass lost after heating.

Mass water = 34.8243 - 27.0351 = 7.7892 grams of water

<u>Step 3:</u> Calculate moles of Cu(NO3)2

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z = moles H2O / moles Cu(NO3)2

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This means we have 3 water molecules in the formula. This makes the formula ofthe hydrate: Cu(NO3)2*3H2O

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