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vlada-n [284]
3 years ago
10

Carbon forms two oxides in which the weight of oxygen combines with 1 g of carbon

Chemistry
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

This is based on the masses of one element, that will be combined with a fixed mass of the other element.

Explanation:

This is based on the masses of one element, that will be combined with a fixed mass of the other element. Thoses masses are in a ratio.

This state we can find in 'The Law of Multiple Proportions, which is part of Dalton's atomic theory

We see that in the 2 compounds, the masses of oxygen, that combine with a fixed mass of carbon , will be in proportion.

For the first oxide we have 1g carbon per 1.33 g Carbon

1g /1.33g  = 0.752

For the second oxide we have 1g carbon per 2.66g Carbon

1g/2.66g = 0.376

Dividing the mass O per g C of the second (larger value) compound:

2.66 / 1.33 = 2   which is the same as 0.752 / 0.376

thus, it means that the masses of oxygen that combine with carbon are in a 2:1 ratio.

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Circle which of the following depend on the amount of matter present:
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It is the boilimg point now aa
4 0
3 years ago
A chocolate bar weighs 4.00 ounces. If the chocolate delivers 2.78 calories per gram, how many
dimulka [17.4K]

Answer:

40.79

Explanation:

an ounce is equal to approximately 28.3 grams.

if you have 4 ounces then it would be equal to about 113.4 grams. then you would divide that by 2.78 which will equal about 40.8

6 0
3 years ago
(1) The solubility of Salt AB2(S) IS 5mol/dm^3.
Svetlanka [38]

Answer:

a. Ksp = 4s³

b. 5.53 × 10⁴ mol³/dm⁹

Explanation:

a. Obtain an expression for the solubility product of AB2(S),in terms of s.

AB₂ dissociates to give

AB₂ ⇄ A²⁺ + 2B⁻

Since 1 mole of AB₂ gives 1 mole of A and 2 moles of B, we have the mole ratio as

AB₂ ⇄ A²⁺ + 2B⁻

1 : 1 : 2

Since the solubility of AB₂ is s, then the solubility of A is s and that of B is 2s

So, we have

AB₂ ⇄ A²⁺ + 2B⁻

[s]        [s]    [2s]

So, the solubility product Ksp = [A²⁺][B⁻]²

= (s)(2s)²

= s(4s²)

= 4s³

b. Calculate the Ksp of AB₂, given that solubility is 2.4 × 10³ mol/dm³

Given that the solubility of AB is 2.4 × 10³ mol/dm³ and the solubility product Ksp = [A²⁺][B⁻]² = 4s³ where s = solubility of AB = 2.4 × 10³ mol/dm³

Substituting the value of s into the equation, we have

Ksp = 4s³

= 4(2.4 × 10³ mol/dm³)³

= 4(13.824 × 10³ mol³/dm⁹)

= 55.296 × 10³ mol³/dm⁹

= 5.5296 × 10⁴ mol³/dm⁹

≅ 5.53 × 10⁴ mol³/dm⁹

Ksp = 5.53 × 10⁴ mol³/dm⁹

6 0
3 years ago
Help pleaseeee. over dilutions in chemistry
atroni [7]

Answer:

5 L

Explanation:

We'll begin by calculating the molarity of the CaCl₂ solution. This can be obtained as follow:

Mole of CaCl₂ = 0.5 mole

Volume = 2 L

Molarity =?

Molarity = mole /Volume

Molarity = 0.5 / 2

Molarity = 0.25 M

Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:

Molarity of stock solution (M₁) = 0.25 M

Volume of stock solution (V₁) = 2 L

Molarity of diluted solution (M₂) = 0.1 M

Volume of diluted solution (V₂) =?

M₁V₁ = M₂V₂

0.25 × 2 = 0.1 × V₂

0.5 = 0.1 × V₂

Divide both side by 0.1

V₂ = 0.5 / 0.1

V₂ = 5 L

Thus the volume of the diluted solution is 5 L

5 0
2 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula
ki77a [65]
The standard atomic weight of a C is 12, and the standard atomic weight of a H is 1.  So to find molar ratio of C and H in the compound: 60.0/12=5, 5.05/1=5. This means the molar ratio of C and H is 5:5, thus 1:1.  Assuming the molecular formula is CnHn, to find molar mass: 12n + 1n = 78.12.  n=78.12/(12+1) = 6.  So the compound's molecular formula is C6H6, benzene.
4 0
3 years ago
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