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mars1129 [50]
2 years ago
8

Since gasses weigh nothing when they are produced in a reaction they do not have to be accounted for.

Chemistry
1 answer:
Cerrena [4.2K]2 years ago
8 0

Answer:

No

Explanation:

You can not have a reaction that produces "no mass". This breaks the law of conservation of mass. When gasses are produced, they will have a specific amount of mass associated with them which means they will have a weight. They will have to be accounted for

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Why are gas bubbles not always a sign of a chemical change?
Mekhanik [1.2K]

Answer: its a reaction

Explanation:

like coke its a reaction between gas and oxygen

3 0
3 years ago
The value of Ka for nitrous acid (HNO2) at 25 ∘C is 4.5×10−4 .a. Write the chemical equation for the equilibrium that correspond
kvv77 [185]

Answers and Explanation:

a)- The chemical equation for the corresponden equilibrium of Ka1 is:

2. HNO2(aq)⇌H+(aq)+NO−2

Because Ka1 correspond to a dissociation equilibrium. Nitrous acid (HNO₂) losses a proton (H⁺) and gives the monovalent anion NO₂⁻.

b)- The relation between Ka and the free energy change (ΔG) is given by the following equation:

ΔG= ΔGº + RT ln Q

Where T is the temperature (T= 25ºc= 298 K) and R is the gases constant (8.314 J/K.mol)

At the equilibrium: ΔG=0 and Q= Ka. So, we can calculate ΔGº by introducing the value of Ka:

⇒ 0 = ΔGº + RT ln Ka

   ΔGº= - RT ln Ka

   ΔGº= -8.314 J/K.mol x 298 K x ln (4.5 10⁻⁴)

  ΔGº= 19092.8 J/mol

c)- According to the previous demonstation, at equilibrium ΔG= 0.

d)- In a non-equilibrium condition, we have Q which is calculated with the concentrations of products and reactions in a non equilibrium state:

ΔG= ΔGº + RT ln Q

Q= ((H⁺) (NO₂⁻))/(HNO₂)

Q= ( (5.9 10⁻² M) x (6.7 10⁻⁴ M) ) / (0.21 M)

Q= 1.88 10⁻⁴

We know that   ΔGº= 19092.8 J/mol, so:

ΔG= ΔGº + RT ln Q

ΔG= 19092.8 J/mol + (8.314 J/K.mol x 298 K x ln (1.88 10⁻⁴)

ΔG= -2162.4 J/mol

Notice that ΔG<0, so the process is spontaneous in that direction.

6 0
3 years ago
Is the normal resting position of an object.
NemiM [27]

Answer:

being stationary relative to a particular frame of reference or another object; when the position of a body with respect to its surroundings does not change with time it is said to be at rest

Explanation:

4 0
3 years ago
Which statement describes the Arrhenius interpretation of acids and bases
KIM [24]
<span>it is limited to situations that involve aqueous solutions of specific compounds

I hope this helps</span>
8 0
3 years ago
Read 2 more answers
Please help I will give brainliest ;3
Hatshy [7]

Answer:

oxygen, carbondioxide

carbondioxide, oxygen

3 0
2 years ago
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