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3 years ago

The price of a computer after discounts was $1200. If the discount was 20%, what was the original sales price?

Mathematics

2 answers:

zmey [24]3 years ago

7 0

$1500!

20% off of $1500 would be $300. $1500 - $300 = $1200. Therefore the original sales price was $1500!

lesantik [10]3 years ago

7 0

Answer:

$1,500

Step-by-step explanation:

The discounted amount is a function of the original amount. The discount when subtracted from the original sales price gives the price after discount.

If the amount after discount is $1200 and the discount is 20%, let the original sales price be x.

Then,

x - (20% × x) = $1200

80% × x = $1200

x = $1,500

The original sales price is $1,500

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alex41 [277]

So I'm going to assume that this question is asking for non extraneous solutions, or solutions that are found in the equation and are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$

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$x(x-2)-3(x-2)=0$

Now you can rewrite the equation as $(x-3)(x-2)=0$

Now, apply the Zero Product Property and solve for x as such:

$x-3=0\\x=3\\\\x-2=0\\x=2$

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

$2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}$

Since both solutions hold true when x = 2 and x = 3, your answer is C. x = 2 or x = 3.

8 0

3 years ago

Is the discriminant of f positive , zero , or negative

Kruka [31]

Answer:

Negative because there's no x-intercepts!

Hope this helps!

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2 years ago

What is the answer to this word problem or how would I solve it

USPshnik [31]

Its a simultaneous equation:
lets make "x" the used games and "y" the new ones

4x + 2y = 84
6x + y = 78. (multiply this by 2 to cancel out y)
12x + 2y = 156

so now we subtract them:
12x - 4x = 156 - 84
x = 9
used games cost $9
new games cost 78 - 6(9) = $24

Janet has $120 but she already bought 3 NEW games so:
120 - 3(24) = $48 left

48/9 = how many used ones she can buy = 5. something

she can buy 5 used

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2 years ago

How can you use the data to understand what happened during the day?

makkiz [27]

What data are you talking about ?

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2 years ago

On the first day after the new moon, 2% of the Moon's surface is illuminated. On the second day, 6% is illuminated. Based on thi

maxonik [38]

Answer:

50%: day 13

100%: day 26

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We are given two days and the amount of the moon that is illuminated. The two days are points on a straight line.

(1, 0.02), (2, 0.06)

y = mx + b

m = (0.06 - 0.02)/(2 - 1) = 0.04

y = 0.04x + b

0.02 = 0.04(1) + b

b = -0.02

y = 0.04x - 0.02

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0.04x - 0.02 = 0.5

0.04x = 0.52

x = 13

y = 100% = 1

0.04x - 0.02 = 1

0.04x = 1.02

x = 25.5

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2 years ago

Read 2 more answers