2C4H10 + 13O2 Right arrow. 8CO2 + 10H2O
What is the mole ratio of butane to carbon dioxide?
ANSWER:
Butane is an organic compound with the formula C4H10 and carbon dioxide is compound (gas) with the formula CO2. So, the balanced coefficient of butane is 2, and that of carbon dioxide is 8. According to thid, the mole ratio of butane to carbon dioxide is 2:8 or 1:4.
Answer:
Ice is less dense than water because of the way it forms a hexagonal crystalline structure. Each water molecule consists of two hydrogen atoms bonded to the bottom of an oxygen atom. ... In the winter, temperatures in a lake get close enough to freezing that the colder water is less dense and floats to the top
Explanation:
Answer:
(a) Three translational degrees of freedom, 2 rotational degrees. 5 total
Cv = 5/2 R; Cp = 7/2 R
(b) and (c) 6 total degrees of freedom ( 3 translational, 3 rotational)
Cv = 3 R ; Cp = 4R
Explanation:
(a) O₂
Oxygen being a diatomic molecule has three translational degrees of freedom and two rotational degrees of freedom since it can move in the three axis and can rotate around two.
(b) H₂O
This is a polyatomic molecule and it has three translational and three rotational degrees of freedom.
(c) Same as water it has three translational degrees of freedom and three rotational degrees of freedom
To calculate the heat capacities we have to make use of the equipartition theorem which tell us that for each degree of freedom imparts 1/2 R to the heat capacity at constant volume.
(a)
5 total degrees of freedom ⇒ Cv = 5/2 R
Cp ( heat capacity at constant pressure) is determined from the relation
Cp - Cv = R
Cp = 7/2 R for O2 molecule
(b) and (c)
Total degrees of freedom 6
Cv = 3 R
Cp = 4 R
Here we are ignoring any contribution of the vibrational modes to the contribution of the heat capacities
Answer:
the value of Kp at 25°C is 2.37 × 10⁻⁴atm³
Explanation:
Given that Kp = 0.116atm
NH₄(NH₂CO₂)(s) ⇄ 2NH₃(g) + CO₂(g)
2x atm xatm
Pt = PNH₃ PCO₂
0.116 = 2x + x
0.116 = 3x
x = 0.116/3
x = 0.039 atm
PNH₃ = 2x =2(0.039) = 0.078 atm
PCO₂ = x = 0.039 atm
Now,
KP = PNH₃² × PCO₂
= 0.078² × 0.039 atm³
= 2.37 × 10⁻⁴ atm³
the value of Kp at 25°C is 2.37 × 10⁻⁴atm³
Answer: D
Explanation: I got it right